I NEED HELP ASAP!!! How do I solve this?
1 answer:
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Answer: 0.038
Step-by-step explanation:
Given: Total games : n= 375
Number of games won by the team that was winning the game at the end of the third quarter. = 300
The proportion (p) of the team that was winning the game at the end of the third quarter:
Critical z-value for 90% confidence: z* = 1.645
Margin of error =
The margin of error in a 90% confidence interval estimate of p
Hence, the required margin of error = 0.038