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Answer:
y = -1/2 x - 13/2
Step-by-step explanation:
what is an equation of the line that is perpendicular to y-4=2(x-6) and passes through (-3,-5)
First, we need the slope of the given line.
y - 4 = 2(x - 6)
y - 4 = 2x - 12
y = 2x - 8
The slope of the given line is 2.
The slopes of perpendicular lines are negative reciprocals, so the slope of the perpendicular is -1/2.
y = -1/2 x + b
We use the given point as x and y and solve for b.
-5 = -1/2(-3) + b
-10 = 3 + 2b
2b = -13
b = -13/2
The equation of the perpendicular line is:
y = -1/2 x - 13/2
Step-by-step explanation:
B.12x + 1
if it helps brainiest lol
Answer:
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<span>y= 2x ^2 - 8x +9
</span>y = a(x - h)2 + k, where (h, k) is the vertex<span> of the parabola
</span>so
y= 2x ^2 - 8x + 9
y= 2x ^2 - 8x + 8 + 1
y = 2(x^2 - 4x - 4) + 1
y = 2(x - 2)^2 + 1 ....<---------<span>vertex form</span>
