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natka813 [3]
3 years ago
5

Which linear equation represents the graph? A)y=3x+6 B)y=3x-3 C)y=-3x+6 D)y=-3x-6

Mathematics
1 answer:
romanna [79]3 years ago
3 0

Answer:

D. y=-3x-6

Step-by-step explanation:

line slopes downwards by 3 and moves to the right by 1. this means the slope is -3. the line crosses the y axis at -6, so the equation for the line is -3x-6

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HELLLLPPPP QUICKKLLLYYYY PLLZZZ VIEW THE QUESTION IN THE PHOTO ATTACHED!!!!
Alekssandra [29.7K]

Answer:

\sqrt{18a}

Step-by-step explanation:

To insert the factor, you must first find its squared value, in this case, 3's squared number is 9 so.....3=\sqrt{9}

Now with square roots, they multiply like any other number

so you end up with\sqrt{9}*\sqrt{2a}  \\\sqrt{9*2a}\\\\\sqrt{18a}

Please leave a thanks!!!

3 0
2 years ago
992×16=? show work please
natulia [17]

              9 9 2
                 1 6
          -----------
           5 9 5 2 
           9 9 2   
          -----------
        1 5,8 7 2      <== 
6 0
4 years ago
I don’t understand this please help
Mrrafil [7]

Answer:

i think BC = 8.5

Step-by-step explanation:

19-(2+6.5+2)

19-10.5

8.5

7 0
3 years ago
Help me please !<br> 4,5 and 6
andreev551 [17]

9514 1404 393

Answer:

  4a. ∠V≅∠Y

  4b. TU ≅ WX

  5. No; no applicable postulate

  6. see below

Step-by-step explanation:

<h3>4.</h3>

a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...

  ∠V≅∠Y

__

b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...

  TU ≅ WX

__

<h3>5.</h3>

The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)

  "No, we cannot prove they are congruent because none of the five postulates or theorems can be used."

__

<h3>6.</h3>

The first statement/reason is always the list of "given" statements.

1. ∠A≅∠D, AC≅DC . . . . given

2. . . . . vertical angles are congruent

3. . . . . ASA postulate

4. . . . . CPCTC

8 0
3 years ago
Solving a right triangle means using given information to find all the angles and side lengths on
nikklg [1K]
All triangles add up to 180 degrees so I don’t get the just of the question but there you go.
4 0
4 years ago
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