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zhuklara [117]
3 years ago
13

Simplify by adding

Mathematics
1 answer:
Musya8 [376]3 years ago
5 0

Answer:

=3x^2-3x-7

Step-by-step explanation:

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

=3x^2+2x-5x-7

\mathrm{Add\:similar\:elements:}\:2x-5x=-3x

=3x^2-3x-7

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Chin canned a number of quart jars and a number of pint jars of tamoatoes from his garden a pint is 16 ounces and a quart us 32
natulia [17]
The total volume of the canned tomato sauce is equal to the sum of those canned in quart jars (32 ounces) and the number of pint jars (16 ounces). If we let p and q be the number of pints and quarts canned, the equation that would best represent the given is,
                                    32q + 16p = 1280
Simplifying the equation by dividing by 16 will give us the final answer of,
                                   2q + p = 80
7 0
3 years ago
Read 2 more answers
Help!!!! f(x)=10x+3 g(x)= -7x-4
Gelneren [198K]

Answer:

8x + 7

Step-by-step explanation:

8 0
3 years ago
How many pages can Jorge print in 3/5 of an hour if he can print 24 pages every 15 minutes?
MariettaO [177]

Answer:

57.6 pages

Step-by-step explanation:

First, you need to identify how many minutes are in 3/5 of an hour:

1 hour = 60 minutes

3/5 of an hour = 3/5 of 60 minutes

= 3/5(60)

= 36

So, you need to find out how many pages can be printed in 36 minutes. To figure this out, a ratio can be used:

15 : 24

36 : p

p represents pages in 36 minutes.

Now, you need to solve the ratio by figuring out what you need to multiply 15 by to get 36 and then multiplying that by 24:

15 * 36/15 = 36

36/15 = 2.4

24*2.4

= 57.6 pages

5 0
3 years ago
the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


4 0
3 years ago
What is the value ?????
worty [1.4K]
Cos x = 15÷17
because cos is adjacent side over hypotenuse.
6 0
3 years ago
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