All categories

3 years ago

8+(-2.25) simplify the answer

Mathematics

2 answers:

guajiro [1.7K]3 years ago

6 0

Answer:

5.75

Step-by-step explanation:

Rashid [163]3 years ago

3 0

the answer would end up as 5.75

You might be interested in

Is y=x^2+7 a linear equation?

tankabanditka [31]

Answer:

No, it is not a linear equation

Step-by-step explanation:

This equation contains the term x², meaning that it is a quadratic function (parabola)

So, it is not a linear equation.

If it were a linear equation, x would not be squared, and the equation would have been in y = mx + b form.

The answer is no, it is not a linear equation.

7 0

3 years ago

Read 2 more answers

NEED HELP ON THIS QUESTION

Tom [10]

Answer: 288

Workings : 16 x 12 =192 (for bottom rectangle bit) 12x 16 =192 then divide 192 by 2 =96 add them together and its 288

3 0

3 years ago

(6x2 - 4x + 11) + ( 4 - x2 – 3x)

Vadim26 [7]

The answer is 27 -9x

5 0

3 years ago

Read 2 more answers

A tank has the shape of a surface generated by revolving the parabolic segment y = x2 for 0 ≤ x ≤ 3 about the y-axis (measuremen

Darina [25.2K]

Answer:

$100\pi\int\limits^9_0 {(\sqrt y)^2(14-y)} \, dy$ ft-lbs.

Step-by-step explanation:

Given:

The shape of the tank is obtained by revolving $y=x^2$ about y axis in the interval $0\leq x\leq 3$ .

Density of the fluid in the tank, $D=100\ lbs/ft^3$

Let the initial height of the fluid be 'y' feet from the bottom.

The bottom of the tank is, $y(0)=0^2=0$

Now, the height has to be raised to a height 5 feet above the top of the tank.

The height of top of the tank is obtained by plugging in $x=3$ in the parabolic equation . This gives,

$H=3^2=9\ ft$

So, the height of top of tank is, $y(3)=H=9\ ft$

Now, 5 ft above 'H' means $H+5=9+5=14$

Therefore, the increase in height of the top surface of the fluid in the tank is given as:

$\Delta y=(14-y)$ ft

Now, area of cross section of the tank is given as:

$A(y)=\pi r^2\\r\to radius\ of\ the\ cross\ section$

Radius is the distance of a point on the parabola from the y axis. This is nothing but the x-coordinate of the point.

We have, $y=x^2$

So, $x=\sqrt y$

Therefore, radius, $r=\sqrt y$

Now, area of cross section is, $A(y)=\pi (\sqrt y)^2$

Work done in pumping the contents to 5 feet above is given as:

$W=D\int\limits^{y(3)}_{y(0)} {A(y)(\Delta y)} \, dy$

Plug in all the values. This gives,

$W=100\int\limits^9_0 {\pi (\sqrt y)^2(14-y)} \, dy\\\\W=100\pi\int\limits^9_0 { (\sqrt y)^2(14-y)} \, dy\textrm{ ft-lbs}$

7 0

3 years ago

Does 3y-x=6 have a slope of -3

inessss [21]

Answer:

Step-by-step explanation:

y=mx+b

applied to the information given:

3y=x+6,

divide both sides by 3

y=1/3x+2

slope is 1/3

8 0

3 years ago