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guapka [62]
3 years ago
14

A rectangular prism and a cylinder have the same height. The length of each side of the prism base is equal to the diameter of t

he cylinder. Which shape has a greater volume? Drag and drop the labels to explain your answer.
Mathematics
1 answer:
NARA [144]3 years ago
5 0

Answer:

The rectangular prism has the greater volume

Step-by-step explanation:

Given

Prism:

Length = Width = a

Height = h

Cylinder

Diameter = a

Height = h

Required

Shape with greater volume

The volume of a rectangular prism is:

Volume = Length * Base * Height

So, we have:

V_1 = a*a*h

V_1 = a^2h

The volume of a cylinder is:

Volume = \pi r^2h

Where

r = \frac{d}{2}

r = \frac{a}{2}

So, we have:

V_2 = \pi *(a/2)^2 h

V_2 = \pi *\frac{a^2}{4} h

\pi = 3.14

So:

V_2 = 3.14*\frac{a^2}{4} h

V_2 = \frac{3.14}{4} a^2h

V_2 = 0.785 a^2h

So, we have:

V_1 = a^2h

V_2 = 0.785 a^2h

Both expressions have the same factor but different coefficient

The expression with greater coefficient has the greater volume

So, the rectangular prism \\ has the greater volume

Because: 1 > 0.785

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Answer: I believe his earnings would be 187$ once he teaches 7 classes.


Step-by-step explanation:

$187-$68=$111

17 x ? = 119

(take the 17$ which is the amount of money he'll earn each class and divide by 111. as seen below:

$111/17$=$6.5 (round to $7)

(you then plug in the 17 for 7 x ? = 119)

7x17=119

now you have to add the 68$ that he will get per month.

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Which of the following statements is true based on the data set shown below?
alisha [4.7K]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
The ratio of the number of dolls Jacky had to the number of dolls Peter had was 5 : 2 but, after Jacky gave 15 dolls to Peter, t
tester [92]

Answer:

35 [$]

Step-by-step explanation:

1) if Peter's sum is p and Jacky's is j, then the ratio 5:2 in the condition can be written j/p=5/2;

2) the phrase 'after Jacky gave 15 dolls to Peter, they have an equal number of dolls' can be written as j-15=p;

3) using the two above it is possible to make up the system of two equations:

\left \{ {{\frac{j}{p} =5/2} \atop {j-15=p}} \right. \ = > \ \left \{ {{j=2.5p} \atop {j-15=p}} \right. \ = > \ \left \{ {{j=25} \atop {p=10}} \right.

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A circular disc has circumference 250 cm.<br> Calculate the radius of the disc.
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3 years ago
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