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cluponka [151]
2 years ago
8

Multiply this please! i dont understand this assignment and need someones help asap!

Mathematics
1 answer:
shepuryov [24]2 years ago
6 0

Answer:

b1 = -21

b2 = 33

b3 = 6

Step-by-step explanation:

I think that it is asking you to multiply 3 by -7, 11 and 2 and those would equal b1,2, and 3

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What is the following product? Assume y >/= 0
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\sqrt{y^3} * \sqrt{y^3}= \sqrt{y^3*y^3}= \sqrt{y^6}=y^{ \frac{6}{2} } =y^3
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3 years ago
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Том и Эми установили будильники на своих телефонах на 6:45. Оба сигнала тревоги звучат одновременно в 6.45. Будильник Тома звучи
Debora [2.8K]

Answer:

36 минут спустя в 7:21

это проблема LCM, поэтому вот как ее решить.

Том звучит через 9, 18, 27, 36 минут после первоначального звучания.

Звуки Эми в 12, 24, 36 минут

Итак, в 7:21, через 36 минут после того, как они ушли, и Том, и Эми проснулись, и они оба опоздали.

-------------------

Translation

36 minutes later at 7:21am

this is a LCM problem so this how to solve it.

Toms sounds at 9, 18, 27, 36 minutes after it initially sounds

Amy’s sounds at 12, 24, 36 minutes

so at 721am 36 minutes after they went off both Tom and Amy when they woken up,they were both late.

8 0
2 years ago
Show that 3 · 4^n + 51 is divisible by 3 and 9 for all positive integers n.​
Leni [432]

Answer:

To prove that 3·4ⁿ + 51 is divisible by 3 and 9, we have;

3·4ⁿ is divisible by 3 and 51 is divisible by 3

Where we have;

S_{(n)} =  3·4ⁿ + 51

S_{(n+1)} = 3·4ⁿ⁺¹ + 51

S_{(n+1)} - S_{(n)} = 3·4ⁿ⁺¹ + 51 - (3·4ⁿ + 51) = 3·4ⁿ⁺¹ - 3·4ⁿ

S_{(n+1)} - S_{(n)} = 3( 4ⁿ⁺¹ - 4ⁿ) = 3×4ⁿ×(4 - 1) = 9×4ⁿ

∴ S_{(n+1)} - S_{(n)} is divisible by 9

Given that we have for S₀ =  3×4⁰ + 51 = 63 = 9×7

∴ S₀ is divisible by 9

Since  S_{(n+1)} - S_{(n)} is divisible by 9, we have;

S_{(0+1)} - S_{(0)} =  S_{(1)} - S_{(0)} is divisible by 9

Therefore S_{(1)} is divisible by 9 and S_{(n)}  is divisible by 9 for all positive integers n

Step-by-step explanation:

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