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3 years ago

Can you simplify a chain of if then statements? if so what do we call it?

1 answer:

6 0

A conditional statement (also called an If-Then Statement) is a statement with a hypothesis followed by a conclusion. ... The hypothesis is the first, or “if,” part of a conditional statement. The conclusion is the second, or “then,” part of a conditional statement.

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In California in 2000, the ballot included an initiative to add "none of the above" to the list of options in all candidate race

sveticcg [70]

Answer:

No, because the sample was randomly selected.

Step-by-step explanation:

In this example, the main element that we need to focus on is the way in which the sample was determined. We learn that the sample was taken in California with 1000 people. However, this sample was random, and the survey was conducted in both English and Spanish. The fact that this was a random sample means that it is representative of the population. The size of the population does not affect the accuracy of a random sample.

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3 years ago

What is 1/15 as a decimal

ElenaW [278]

1/15 as a decimal would be 0.6666666......

Or you can round that off to 0.67

7 0

3 years ago

Read 2 more answers

16/25 in decimal form

lidiya [134]

16/25 in decimal form is 0.64

5 0

3 years ago

Read 2 more answers

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

4 0

2 years ago

111111111111111111111111111111111111111111111111111

Illusion [34]

Answer:

x = 4

Step-by-step explanation:

Step 1: Subtract 4 from both sides.

5x+4−4=24−4

5x=20

Step 2: Divide both sides by 5.

x=4

you welcome love

6 0

2 years ago

Read 2 more answers