Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
y intercept is 5. x intercept is 5/7
Answer:
18z 2+17z+4
Step-by-step explanation:
it hard try to give more point
14(8-W)=0
(14*8)-(14*W)=0
112-14W=0
-112 -112
------------------- The answer is 8
-14W= -112
-14W/(-14)= -112/(-14)
W=8
Answer:
(y-(-2))/(x-(-1)= (-2-4)/(-1-3)
(y+2)/(x+1)= (-6)/(-4)
(y+2)/(x+1)= (3/2)
Cross multiplying
2y+4= 3x+3
3x-2y-1=0
