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melamori03 [73]
3 years ago
13

There are 1,000 meters in 1 kilometer. Convert 5.000 meters to kilometers?​

Mathematics
1 answer:
NemiM [27]3 years ago
7 0
It says the numbers 5.000 but i think you mean 5,000 so it would be 5 kilometers
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Instructions:Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Aleks [24]
Call T the price of the T-shirts and P de price of the jeans

Initially (without discount)
2T + P = 40

One month later (half prices)
2 (T/2) + 5(P/2) = 60
T +5P/2 = 60

To solve the system of equations multiply the second equation by 2 and substract it from the first equation

   2 T + 5P = 120
- (2 T +   P = 40 )
________________

           4P = 80

P = 80/4
P = 20

From 2T + P = 40

T = (40 - P) / 2 = (40 -20) / 2 = 20/2 = 10.

The price of a T-shirt is $10 and the price of a pair of jeans is $20.
4 0
3 years ago
Is the value of 8 in 345,802 ten times greater or smaller than the value of 8 in 758,910
german

Answer:

Yes

Step-by-step explanation:

One is in the hundreds and one is in the thousands. 100x10=1000

7 0
2 years ago
The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) for Determine
salantis [7]

The question is incomplete. Here is the complete question.

The probability density function of the time to failure of an electronic component in a copier (in hours) is

                                              f(x)=\frac{e^{\frac{-x}{1000} }}{1000}

for x > 0. Determine the probability that

a. A component lasts more than 3000 hours before failure.

b. A componenet fails in the interval from 1000 to 2000 hours.

c. A component fails before 1000 hours.

d. Determine the number of hours at which 10% of all components have failed.

Answer: a. P(x>3000) = 0.5

              b. P(1000<x<2000) = 0.2325

              c. P(x<1000) = 0.6321

              d. 105.4 hours

Step-by-step explanation: <em>Probability Density Function</em> is a function defining the probability of an outcome for a discrete random variable and is mathematically defined as the derivative of the distribution function.

So, probability function is given by:

P(a<x<b) = \int\limits^b_a {P(x)} \, dx

Then, for the electronic component, probability will be:

P(a<x<b) = \int\limits^b_a {\frac{e^{\frac{-x}{1000} }}{1000} } \, dx

P(a<x<b) = \frac{1000}{1000}.e^{\frac{-x}{1000} }

P(a<x<b) = e^{\frac{-b}{1000} }-e^\frac{-a}{1000}

a. For a component to last more than 3000 hours:

P(3000<x<∞) = e^{\frac{-3000}{1000} }-e^\frac{-a}{1000}

Exponential equation to the infinity tends to zero, so:

P(3000<x<∞) = e^{-3}

P(3000<x<∞) = 0.05

There is a probability of 5% of a component to last more than 3000 hours.

b. Probability between 1000 and 2000 hours:

P(1000<x<2000) = e^{\frac{-2000}{1000} }-e^\frac{-1000}{1000}

P(1000<x<2000) = e^{-2}-e^{-1}

P(1000<x<2000) = 0.2325

There is a probability of 23.25% of failure in that interval.

c. Probability of failing between 0 and 1000 hours:

P(0<x<1000) = e^{\frac{-1000}{1000} }-e^\frac{-0}{1000}

P(0<x<1000) = e^{-1}-1

P(0<x<1000) = 0.6321

There is a probability of 63.21% of failing before 1000 hours.

d. P(x) = e^{\frac{-b}{1000} }-e^\frac{-a}{1000}

0.1 = 1-e^\frac{-x}{1000}

-e^{\frac{-x}{1000} }=-0.9

{\frac{-x}{1000} }=ln0.9

-x = -1000.ln(0.9)

x = 105.4

10% of the components will have failed at 105.4 hours.

5 0
3 years ago
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