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malfutka [58]
3 years ago
10

Find the distance between the two points. ​(2​,7​) and ​(−18​,22​)

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

d = 25

Step-by-step explanation:

d = sqrt( (y2 - y1)^2 + (x2 - x1)^2  )

d = sqrt( (7  - 22)^2 + (2 - (-18) )^2  )

d = sqrt (  (- 15)^2 + 20^2 )

d = sqrt ( (225) + (400) )

d = sqrt (625)

d = 25

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The formula for area of a circle is A=rsquared*3.14. Divide 5.5/2 to get 2.75. Mulitply 2.75 times 2.75 to get approximately 7.56. Then, multiply that times 3.14 to get approximately 23.74.

Answer=23.74 yards
3 0
3 years ago
0.5% of 490 is what number  show work please
Genrish500 [490]
You would set it up: .5/100 = x/490 and then cross multiply .5 time 490 and 100 times x, and end up with: 245=100x. divide by 100, and get 2.45
6 0
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Find the commission.
alexandr1967 [171]
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4 0
4 years ago
A city council consists of eight Democrats and eight Republicans. If a committee of six people is selected, find the probability
saw5 [17]

Answer:

39.16% probability of selecting three Democrats and three Republicans

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question, the order in which the people are selected is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes:

3 Democrats, from a set of 8.

3 Republicans, from a set of 8.

D = C_{8,3}*C_{8,3} = (C_{8,3})^{2} = (\frac{8!}{3!5!})^{2} = 56^2 = 3136

Total outcomes:

6 people from a set of 16.

T = \frac{16!}{6!10!} = 8008

Probability:

p = \frac{D}{T} = \frac{3136}{8008} = 0.3916

39.16% probability of selecting three Democrats and three Republicans

5 0
3 years ago
I need to verify identity functions for a one to one function.
Eddi Din [679]

We have the function

f(x)=(x+6)^3

1. For f^-1:

Let y = f(x) = (x+6)^3

Switch x and y to get:

x=(y+6)^3

And solve for y

\begin{gathered} x^{\frac{1}{3}}=y+6 \\ x^{\frac{1}{3}}-6=y+6-6 \\ x^{\frac{1}{3}}-6=y \end{gathered}

And we have y = f^-1(x)

Answer blank 1:

f^{-1}(x)=x^{\frac{1}{3}}-6

2. For f o f^-1 (x):

(f\circ f^{-1})(x)=f(f^{-1}(x))

And solve

\begin{gathered} =f(x^{\frac{1}{3}}-6) \\ =(x^{\frac{1}{3}}-6+6)^3 \\ =(x^{\frac{1}{3}})^3 \\ =x \end{gathered}

answer blank 2

x^{\frac{1}{3}}-6

answer blank 3

x^{\frac{1}{3}}-6

answer blank 4

x^{\frac{1}{3}}

3. For f^-1 o f:

(f^{-1}\circ f)(x)=f^{-1}(f(x))

Solve

\begin{gathered} =f^{-1}((x+6)^3) \\ =\sqrt[3]{(x+6)^3}-6 \\ =x+6-6 \\ =x \end{gathered}

answer blank 5

(x+6)^3

answer blank 6

(x+6)^3

answer blank 7

x+6

4 0
1 year ago
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