Answer:
Therefore, the only ordered pair that is a valid solution is B)
Step-by-step explanation:
In order for a pair to be a solution of a function, the equation must be valid when said point is used in it. We will check for each point:
A) (-1, 4)
f(x) = 3*x - 1
4 = 3*(-1) - 1
4 = -3 -1
4 = -4 (invalid)
B) (-1, -3)
f(x) = 3*x - 1
-3 = 3*(-1) - 1
-3 = -3 -1
-3 = -4
C) (-1, -4)
f(x) = 3*x - 1
-4 = 3*(-1) - 1
-4 = -3 -1
-4 = -4 (valid)
D) (-1, 2)
f(x) = 3*x - 1
-1 = 3*(2) - 1
-1 = 6 -1
-1 = 5 (invalid)
Answer:
I only used two steps: 3) then 6) then 1).
Step-by-step explanation:
Ok, if x-5 is a factor of p(x), then p(5)=0 by factor theorem.
This also goes the other way around:
If p(5)=0 then x-5 is a factor of p(x) by factor theorem.
Let's check. I'm going to evaluate p(x) for x=5.
This implies x-5 is a factor since we have p(5)=0.
The first step I did was 3) evaluate p(x) for x=5.
The second step I did 6) simplify and find the remainder. I did this when I was evaluating p(5); that was a lot of simplification and then I found the remainder to be 0 after that simplification. The last step was 1) apply the factor theorem, the remainder is 0 so x-5 is a factor of p(x).
Answer:
Step-by-step explanation:
Given
Pizza hut charges $7 for a cheese pizza
Each additional topping costs $0.50
Considering y as the cost of pizza and x be the amount of topping added
Cost of a pizza with toppings
Here, the slope of the equation is
Y-intercept is equivalent to price of base pizza i.e.
Well I think that for this problem we should multiply 3x1/3 which is 1 whole. Sorry if I'm incorrect.