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Nitella [24]
3 years ago
12

-2 1/4 + 8 + (-1 3/4)

Mathematics
2 answers:
krok68 [10]3 years ago
7 0

Answer:

4

Step-by-step explanation:

padilas [110]3 years ago
4 0

Answer:

Your answer is 4:)

Step-by-step explanation:

have a great day! brainliest?

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Identify the Minimum, First Quartile, Median, Third Quartile, and Maximum for the data.
Ymorist [56]

Answer:

I think we are missing data, so this is impossible to answer.

3 0
3 years ago
Statuary Hall is an elliptical room in the United States Capitol in Washington, D.C. The room is also called the Whispering Gall
dalvyx [7]

Answer: a) \frac{x^{2} }{2352.25 } + \frac{y^{2} }{529} = 1

b) The distance of two foci is 85.4 feet

c) Area = 3502.67 square feet

Step-by-step explanation: a) An ellipse has the equation in the form of:

\frac{x^{2} }{a^{2} }+\frac{y^{2} }{b^{2} } = 1, where a is the horizontal axis and b is the vertical axis.

For the Statuary Hall, a = \frac{97}{2} = 48.5 and b = \frac{46}{2} = 23, so the equation will be

\frac{x^{2} }{2352.25 } + \frac{y^{2} }{529} = 1.

b) To determine the distance of the foci, we have to calculate 2c, where c is the distance between one focus and the center of the ellipse. To find c, as a, b and c create a triangle with a as hypotenuse:

a^{2} = b^{2} + c^{2}

c^{2} = a^{2} - b^{2}

c = \sqrt{48.5^{2} - 23^{2} }

c = 42.7

The distance is 2c, so 2·42.7 = 85.4 feet.

The two foci are 85.4 feet apart.

c)The area of an ellipse is given by:

A = a.b.π

A = 48.5 · 23 · 3.14

A = 3502.67 ft²

The area of the floor room is 3502.67ft².

3 0
3 years ago
The probability of picking two black marbles from a box at random without replacement is 10/91 .
sasho [114]
The probability of the 2 events are multiplied to get the result 10/91

so we have the relation 5/14 *  x  = 10/91

where x is the probability of drawing the second black

so x =  10/91 * 14/5 =  4/13   answer
8 0
3 years ago
Read 2 more answers
It took Mike 1/3 hour to mow 1/4 of a yard. How long will it take him to finish the entire yard?
Kazeer [188]

Answer:

4/3 of an hour, or 1.33 hours

Step-by-step explanation:

It took Mike 1/3 of an hour to mow 1/4 of the yard. This means when it has been 1 full hour, he would have mowed 3/4 of the yard, because \frac{1}{3} *3=1 hour. Because of this, we can multiply 1/3 by 4, because he has to mow 4 parts of his lawn, and he can do 1 part in 1/3 of an hour.

\frac{1}{3} *\frac{4}{4} =4/3 hours

3 0
2 years ago
In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it
gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0
3 years ago
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