Question

What is the value of x? Round to the nearest tenth.

Answer 1

Answer:

D. 10.2

Step-by-step explanation:

Since the triangle is a right triangle we can use the Pythagorean theorem.

I will call the hypotenuse $h$, so in this case:

$h=19$

and one leg will be $l$, in this case:

$l=16$

and the unknown for this problem is the other leg which in the image is called $x$.

So the formula for the  Pythagorean theorem:

$h^2=l^2+x^2$

clearing for x:

$x^2=h^2-l^2\\x=\sqrt{h^2-l^2}$

substituting $h=19$ and $l=16$:

$x=\sqrt{19^2-16^2}\\ x=\sqrt{361-256}\\ x=\sqrt{105}\\ x=10.2$

the value of x is option D. 10.2

Answer 2

Ans is d (19^2-256)^0.5=10.2