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nlexa [21]
3 years ago
10

To use an outline for writing a formal business document what should you do after entering your bottom line statement

Computers and Technology
1 answer:
oksano4ka [1.4K]3 years ago
6 0

Answer:

enter each major point from the outline on a separate line

Explanation:

<u></u>

<u>Bottom Line</u>

Total income of the company after deducting all the expenses from revenue is called Bottom Line. It is also referred to as net profit.

<u>Outline of Document</u>

The structure of document that is generated with the help of title, major headings and major points to map out the document.

So, After calculating Bottom line statement, outline of document is written that shows all major points of document to summarize the business.

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3 years ago
Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria
butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

           print("Equilateral Triangle")

       elif side1 == side2 or side1 == side3 or side2 == side3:

           print("Isosceles Triangle")

       else:

           print("Scalene Triangle")

   else:

       print("Invalid Triangle")

else:

   print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

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Compared with a star topology, a hierarchical topology: a. is more effective at handling heavy but short bursts of traffic. b. a
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Answer:

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When a router forwards incoming packets closer to their destination hosts, this is called?
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