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mel-nik [20]
3 years ago
8

Please help me please​

Mathematics
1 answer:
sveticcg [70]3 years ago
4 0

Answer:

.

Step-by-step explanation:

If you need any explanation you can communicate with me

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A bag contains 35 marbles, 11 of which are red. A marble is randomly selected from the bag, and it is blue. This blue marble is
Ilia_Sergeevich [38]

Answer:

11 red + 24 blue = 35 marbles

If 1 blue is withdrawn

11 red + 23 blue = 34 marbles

P = 23 / 34 = .38   probability of drawing blue marble

6 0
2 years ago
If she will buy 35 T-shirts, 45 pairs of shorts, and 25 windbreakers, what will be her total cost?
antiseptic1488 [7]
$105 because 35+45+25=105.

I hope this helped you!

:D
5 0
3 years ago
What is the answer? I do not know this one or understand how to do it?
coldgirl [10]

Answer:

The answer is 1 over 3.

Step-by-step explanation:

All you had to do was simplify it.

6 0
3 years ago
I dont know what answer is i need help
Llana [10]

Answer:

12

Step-by-step explanation:

Let's look at the following exponent rule below:

\frac{x^{a} }{x^{b} } = x^{a-b}

We can apply this rule to the problem given to help us find the final answer by taking each exponent and <em>subtracting them</em>. Let's illustrate this below:

\frac{12^{-4} }{12^{-5} } =12x^{-4-(-5)}=12^{-4+5} =12^{1} =12

Hopefully this was helpful! Let me know if you have any more questions.

8 0
2 years ago
Read 2 more answers
Which of the following events has an expected value that is in the sample space? A. tossing a number cube once B. flipping a coi
neonofarm [45]

A) The event is "tossing a number cube once"

The sample space of this event is {1,2,3,4,5,6}.

The expected value of this event is  

1\times \frac{1}{6}+2\times \frac{1}{6}+3\times \frac{1}{6}+4\times \frac{1}{6}+5\times \frac{1}{6}+6\times \frac{1}{6}\\ \\ =\frac{1}{6}+\frac{1}{3}+\frac{1}{2}+\frac{2}{3}+\frac{5}{6}+1\\ \\ =\frac{7}{2} = 3.5

Since 3.5 is not in the sample space of the event. Therefore, option (A) is not correct.

(B) The event is "Flipping a coin"

Sample space of this event is {HH,TT,HT,TH}

Since sample space of this event is not numbers, therefore, this cannot be the correct option either.

(C) The event is, "Randomly picking a number between 1 and 9, inclusive."

The sample space of this event is {1,2,3,4,5,6,7,8,9}.

Expected value of this event is \frac{1}{9}(1+2+3+4+5+6+7+8+9) = \frac{1}{9}(45) = 5

Since 5 is the expected value and it is present in the sample space for this event. Therefore, option (C) is a correct choice.

(D) The sample is "Randomly picking a number between one and ten, inclusive".

The sample space of this event is {1,2,3,4,5,6,7,8,9,10}.

Therefore, expected value of the event is \frac{1}{10}(1+2+3+4+5+6+7+8+9+10) = \frac{1}{10}(55)=5.5

Since 5.5 is not present in the sample space of this event. Therefore, option (D) is not correct either.

Hence, the correct choice is option (C).


4 0
3 years ago
Read 2 more answers
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