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Naily [24]
3 years ago
7

2) Simplify the expression: - - 1 (6x – 10).

Mathematics
1 answer:
makkiz [27]3 years ago
7 0

Answer:

6x-10

Step-by-step explanation:

see image below

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Does anyone know this?
postnew [5]
I believe the second question is Angle-Side-Angle
8 0
3 years ago
1. Using the Product Rule of Probability, calculate the chances of picking a red bean out of a bag with 1 red bean and 49 white
REY [17]

Answer:

0

Step-by-step explanation:

The probability of picking one red bean out of total 50 beans (one red and 49 whites). = 1/50

Now, chances of picking the one red bean out of a bag with 1 red bean and 49 white beans twice in a row is case of conditional probabilty where we can use  the Product Rule of Probability

= 1/50*0/49 = 0 [ There is only one red and it is ready picked in the first draw]

6 0
3 years ago
The function f(x) = 37x + 20 models the total cost for Rachel to be a member at a gym for x months. What can be interpreted from
beks73 [17]

" Rachel must pay a $20 membership fee to join the gym " can be interpreted from the y-intercept of the function ⇒ D

Step-by-step explanation:

The form of the linear function is f(x) = mx + b, where

  • m is the slope (rate of change) of the function
  • b is the y-intercept (initial amount) of the function

∵ f(x) = 37 x + 20 models the total cost for Rachel to be a member

   at a gym for x months

∵ f(x) = m x + b

∴ m = 37 and b = 20

∵ m represents the rate of change

- That means she must to pay 37 per month for x months

∴ Rachel must pay $37 per month to use the gym

∵ b represents the initial amount

- That means she pays a fixed amount one time

∴ Rachel must pay a $20 membership fee to join the gym

" Rachel must pay a $20 membership fee to join the gym " can be interpreted from the y-intercept of the function

Learn more:

You can learn more about the linear function in brainly.com/question/1284310

#LearnwithBrainly

3 0
4 years ago
Please help! <br> -<br> -<br> -<br> -<br> -
Jlenok [28]
The answer has to be in y-intercept form. Which is y=mx+b and b can also be neg. y=mx-b. The m is your slope and b is your y-intercept. So A’s slope counting from 3 on the y axis to 1 on the x-axis which is down 2 over 1 so it will be -2/1. And your y intercept is 3. The equation is y=-2x+3. For B its the same thing but no graph. Remember that slope is RISE over RUN. So since the number is on the bottom of the line the rise is 4 and the run is 1. So in this case 10 is your y-intercept. Which means you equation is y=4x+10.

5 0
3 years ago
Find the area of each parallelogram. What is the relationship between the areas?
castortr0y [4]

Answer:

Area of parallelogram is given by:

A = bh

where b is the base and h is the height of parallelogram.

In parallelogram TQRS.

Coordinate of TQRS are;

T(8, 16), Q(4, 4), R(16, 4) and S(20, 16)

Coordinate of T'Q'R'S' are;

T'(2, 4), Q'(1, 1), R'(4, 1) and S'(5, 4)

Find the length of QR and PT:

Using distance(D) formula:

D = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

QR = \sqrt{(4-16)^2+(4-4)^2} =\sqrt{(-12)^2+0}= \sqrt{144}= 12 units

Similarly;

For PT:

From the graph:

P(8, 4) and T(8, 16), then

PT = \sqrt{(8-8)^2+(4-16)^2} =\sqrt{(-0)^2+(-12)^2}= \sqrt{144}= 12 units

In parallelogram TQRS

PT represents the height and QR represents the base of the parallelogram respectively.

then;

Area of parallelogram TQRS = QR \cdot PT

⇒Area of parallelogram TQRS = 12 \cdot 12 = 144 unit square.

Now, in parallelogram T'Q'R'S'

Q'R' represents the base and P'T' represents the height of the parallelogram respectively.

here, P'(2, 1)

Find the length of Q'R' and P'T':

Q'R' = \sqrt{(1-4)^2+(1-1)^2} =\sqrt{(-3)^2+0}= \sqrt{9}= 3 units

P'T' = \sqrt{(2-2)^2+(1-4)^2} =\sqrt{(-0)^2+(-3)^2}= \sqrt{9}= 3 units

Then;

Area of parallelogram T'Q'R'S' = Q'R' \cdot P'T'

Area of parallelogram T'Q'R'S' = 9 \cdot 9= 81 unit square.

Now, we have to find the relationship between the areas.

\frac{\text{Area of parallelogram TQRS}}{\text{Area of parallelogram T'Q'R'S'}} = \frac{144}{81}

then;

the relationship between the areas of TQRS and T'Q'R'S' is:

\text{Area of parallelogram TQRS} = \frac{144}{81} \cdot {\text{Area of parallelogram T'Q'R'S'}



7 0
3 years ago
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