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lyudmila [28]
4 years ago
8

Patrick is doing a card trick using a standard 52-card deck with four suits: hearts, diamonds, spades, and clubs. He shows his f

riend a card, replaces it, and then shows his friend another card. Give the probability that the first card is not a club and the second card is not a heart.
Mathematics
2 answers:
garik1379 [7]4 years ago
7 0
Probability that the first card is not a club is 1 minus probability that it is a club. i.e. 1 - 1/4 = 3/4
Probability that the second card is not a heart is 1 minus probability that it is a heart. i.e. 1 - 1/4 = 3/4
Probability that the first card is not a club AND the second card is not a heart is 3/4 x 3/4 = 9/16
jeyben [28]4 years ago
5 0
There are a total of 52 cards in a deck- that is 4 cards for each shape: heart, diamond, spade and club and 13 numbers. There are thus, 13 cards with club shape and 13 cards with a heart shape. Hence the probability that the first card is not a club is (52-13)/52 = 3/4  and the second card is not a heart (51-13)/51 = 38/51 is equal to 3/4 *<span>38/51</span> equal to 19/34
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Michaels account overdrafts $75.00. write an absolute value to represent the overdraft
Klio2033 [76]

Overdrafting is when you deposit you're money in a bank account so it could either be +75 or -75 both of them might be correct.

8 0
3 years ago
A suburban high school has a population of 1376 students. The number of students who participate in sports is 649. The number of
Afina-wow [57]

108 / 1376 is the probability that a student participates in both sports and music.

<u>Step-by-step explanation:</u>

It is given that,

A suburban high school has a population of 1376 students.

  • Let the event A be the no.of students participated in sports.
  • Let the event B be the no.of students participated in music.

The number of students who participate in sports is 649.

The number of students who participate in music is 433.

<u>To find the probability of event A (sports) :</u>

P(sports) = No.of students participated in sports / Total students.

⇒ 649 / 1376

∴ P(A) = 649 / 1376

<u>To find the probability of event B (music) :</u>

P(music) = No.of students participated in music / Total students.

⇒ 433 / 1376

∴ P(B) = 443 / 1376

From the question, we know that the probability that a student participates in either sports or music is 974 /1376.

∴ P(A∪B) = 974 / 1376

<u>To find the probability that a student participates in both sports and music :</u>

The formula used here is,

P(A∩B) = P(A) + P(B) - P(A∪B)

⇒ 649 / 1376 + 433 / 1376 - 974 /1376

⇒ 108 / 1376

∴ P(A∩B) = 108 / 1376

5 0
3 years ago
Please help meeeee....I will give brainliest! help a girl out!!!!!
Irina-Kira [14]

Answer:

B) Beth went back toward her origin.

Step-by-step explanation:

From 0 to 6, the graph increases.  The dependent variable in this case is position and the independent variable is time; this means for this portion of the graph, as time increases the position increases as well.

From 6 to 10, the graph decreases.  As time increases the position decreases.  This means she goes back to her original position.

6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP! I don’t recall how to do this!
MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

(1.05)^x=1.885

In order to solve for x, we have to get it out from its position of an exponent.  Do that by taking the natural log of both sides:

ln(1.05)^x=ln(1.885)

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

x=\frac{ln(1.885)}{ln(1.05)}

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

ln(x*x^2)=5

Simplifying gives you

ln(x^3)=5

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

ln(x)=\frac{5}{3}

Take the inverse ln by raising each side to e:

e^{ln(x)}=e^{\frac{5}{3}}

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

\frac{1}{2}=e^{.1x}

"Undo" that e by taking the ln of both sides:

ln(.5)=ln(e^{.1x})

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others.  Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

(2^2)^x-6(2)^x=-8

Now we will bring over the -8 by adding:

(2^2)^x-6(2)^x+8=0

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution.  Let's let u=2^x

When we do that, we can rewrite the polynomial as

u^2-6u+8=0

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor.  Now we have to put it back in:

2^x=4,2^x=2

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

2^2=2^x

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

2^x=2^1

Now that the bases are the same, we can say that

x = 1

5 0
3 years ago
In the equation y = 8x - 2, name the slope (m) and the y-intercept (b). Type in the value for each below. *
kozerog [31]

y = mx + b

m = Slope

b = y-intercept

y = 8x - 2

m = 8

b = -2

y = 1/4x + 6

m = 1/4

b = 6

5 0
3 years ago
Read 2 more answers
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