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3 years ago

If f(x) = 3x + 7, find: f(3) = [?] Enter

1 answer:

5 0

F(3)= 16. Essentially, you need to substitute 3 for x, which would look like this: 3(3) + 7. Then, by using PEMDAS/the order of operations, multiply 3 by 3 to get 9, and then add 7 to get 16.

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3 years ago

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3 years ago

USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole

Zepler [3.9K]

Answer:

$\mu =E(X) = 0*0.207+1*0.367+ 2*0.227+ 3*0.162+ 4*0.036+ 5*0.001= 1.456$

For the variance we need to calculate first the second moment given by:

$E(X) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = 0^2*0.207+1^2*0.367+ 2^2*0.227+ 3^2*0.162+ 4^2*0.036+ 5^2*0.001= 3.33$

And the variance is given by:

$\sigma^2 = E(X^2) - [E(X)]^2 = 3.334 -[1.456]^2 =1.21$

And the deviation is:

$\sigma = \sqrt{1.214} = 1.10$

Step-by-step explanation:

For thi case we have the following distribution given:

X 0 1 2 3 4 5

P(X) 0.207 0.367 0.227 0.162 0.036 0.001

For this case the expected value is given by:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$\mu =E(X) = 0*0.207+1*0.367+ 2*0.227+ 3*0.162+ 4*0.036+ 5*0.001= 1.456$

For the variance we need to calculate first the second moment given by:

$E(X) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = 0^2*0.207+1^2*0.367+ 2^2*0.227+ 3^2*0.162+ 4^2*0.036+ 5^2*0.001= 3.33$

And the variance is given by:

$\sigma^2 = E(X^2) - [E(X)]^2 = 3.334 -[1.456]^2 =1.21$

And the deviation is:

$\sigma = \sqrt{1.214} = 1.10$

3 0

4 years ago