<span>r²sin²θ = 16rcosθ </span>
<span>rsin²θ = 16cosθ </span>
<span>r = 16cosθ / sin²θ </span>
<span>r = 16cotθcscθ</span>
Answer:
Ques 16)
We have to simplify the expression:
Ques 17)
Ques 18)
Let the blank space be denoted by the quantity 'x'.
Ques 19)
Let the missing quantity be denoted by 'x'.
Im guessing the first answer
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm