Answer:
The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.
Explanation:
Given that,
Initial velocity u= 128 ft/sec
Equation of height
....(I)
(a). We need to calculate the maximum height
Firstly we need to calculate the time
From equation (I)
Now, for maximum height
Put the value of t in equation (I)
(b). The number of seconds it takes the object to hit the ground.
We know that, when the object reaches ground the height becomes zero
Hence, The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.
Explanation:
Let a is the linear acceleration of the descending sphere. It is given by,
.......(1) (change in velocity)
Let 
is the angular acceleration α of the rotating wheel. It is given by :
............(2) (change in angular velocity)
Dividing equation (1) and (2) we get :
Since, 
Hence, this is the required solution.
The answer is uniformitarianism.
Answer: The "as-is" and the "to-be" process model are business process models which defines the current state of a business process in an organization and the future State. Their primary goals is to determine what the problem is and then how to solve the problem. Both processes starts with the first stage of understanding what the process problem is and to determine the problem and the possible solutions
Explanation:
Answer:
Reverses its direction of travel precisely as it reaches the eggs
Explanation:
At the top of the motion: The spring is stretched the least, so, the potential energy of the spring is at a minimum. The mass is lifted as high as it will go, so, the potential energy due to gravity is at a maximum.
When the spring is now at the maximum, now, the maximum potential at the maximum height is
Equal to the energy stored in spring
And the energy stored in spring.
The net force on the object can be described by Hooke’s law, and so the object undergoes simple harmonic motion. Note that the initial position has the vertical displacement at its maximum value X; v is initially zero and then negative as the object moves down; and the initial acceleration is negative, back toward the equilibrium position and becomes zero at that point.
So this apply to the body given, when it get to the egg and it is released the weight will move upward 1m above the equilibrium point and it will return downward 1m below the equilibrium point, that is reverses its direction of travel precisely as it reaches the eggs.
