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3 years ago

5. Read the final paragraph on the opposite page. What is the speed of the car in km/h?

Physics

1 answer:

Vera_Pavlovna [14]3 years ago

8 0

Answer:

yhjkhjjoknhtyhhjhhynn

jjjjjtsstujbfryjbctybggn

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A container with 3 kg of pure water at a temperature of 12 degrees Celsius is placed in a refrigerator where the air temperature

qaws [65]

Answer:

100 368 J

Explanation:

Heat lost by the water = heat gained by the air ( which the 'frige works to expel and keep at 4 degrees)

specific heat for water ( in joules) : 4182 J / kg-C

3 kg * 4182 J / kg-C * (12-4 C) = 100 368 J

6 0

2 years ago

A stone is dropped at t = 0. A second stone, with 6 times the mass of the first, is dropped from the same point at t = 59 ms. (a

xxTIMURxx [149]

Answer: $y_{com}=0.707 m$

$v_{com}=3.713 m/s$

Explanation:

Given

first stone mass is m

second stone mass is 6 m

distance traveled by first stone in 430 ms

$y_1=ut+\frac{at^2}{2}$

$y_1=0+\frac{g(0.43)^2}{2}$

$y_1=0.9069 m$

Distance traveled by stone 2 in t=430-59=371 ms

$y_2=ut+\frac{at^2}{2}$

$y_2=0+\frac{g(0.0.371)^2}{2}$

$y_2=0.674 m$

velocity of first stone after t=0.43 s

$v_1=u+at$

$v_1=0+9.8\times 0.43=4.214 m/s$

velocity of second stone after t=0.371 s

$v_2=u+at$

$v_2=0+9.8\times 0.371=3.63 m/s$

Position of Center of mass of system

$y=\frac{y_1m_1+y_2m_2}{m_1+m_2}$

$y=\frac{0.9069\times m+0.674\times 6m}{m+6m}$

$y=\frac{4.95m}{7m}=0.707 m$

Velocity of COM

$v_{com}=\frac{v_1m_1+v_2m_2}{m_1+m_2}$

$v_{com}=\frac{4.214\times m+3.63\times 6m}{m+6m}$

$v_{com}=3.713 m/s$

6 0

4 years ago

Which of the following is an example of changing momentum?!

ExtremeBDS [4]

Answer:

B!!!

Explanation:

5 0

3 years ago

Read 2 more answers

Which is hotter 30celcius or 30farenheit

natima [27]

Answer:

30 celsius

Explanation:

30 celsius = 86 fahrenheit

4 0

3 years ago

Normal conversation has a sound level of about 60 db. How many times more intense must a 100-hz sound be compared to a 1000-hz s

vampirchik [111]

Answer:

5.65 times

Explanation:

60 db sound is equal to 60 phons sound when frequency is kept at 1000Hz.

But when the frequency of sound is changed to 100 Hz , according to equal loudness curves , the loudness level on phon scale will be 35 phons.

A decrease of 10 phon on phon- scale makes sound 2 times less loud

Therefore a decrease of 25 phons will make loudness less intense by a factor equal to 2²°⁵ or 5.65 less intense . Therefore intensity at 100 Hz

must be increased 5.65 times so that its intensity matches intensity of 60 dB sound at 1000 Hz frequency.

6 0

4 years ago