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stiv31 [10]
3 years ago
14

PLZZZ HELP

Physics
1 answer:
zubka84 [21]3 years ago
5 0

Answer:

C

Explanation:

A feather falls from one end of a tube to the other inside a vacuum.

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The table below shows the acceleration of gravity on different bodies in the
Aloiza [94]

Answer:

Pluto

because the the gravitation strength is small, so it will be accelerating slow

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A 1-kg collar (located at point (2,2) from the origin) is pulled along a vertical, frictionless bar with a force of 10 N applied
faltersainse [42]

Answer:

The acceleration of the collar is 10 m/s²

Explanation:

Given;

mass of the collar, m = 1 kg

applied force on the bar, F = 10 N

The acceleration of the collar can be calculated by applying Newton's second law of motion;

F = ma

where;

F is the applied force

m is mass of the object

a is the acceleration

a = F / m

a = 10 / 1

a = 10 m/s²

Therefore, the acceleration of the collar is 10 m/s²

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2 years ago
The diagram below represents a light ray striking the surface of a flat, shiny object.
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Answer:

<em><u>option</u></em><em><u> (</u></em><em><u>C)</u></em><em><u> </u></em><em><u>is </u></em><em><u>right</u></em><em><u> answer</u></em>

Explanation:

I think it's helps you

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3 years ago
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The colour of star depend on its temperature, why?​
taurus [48]

<em>Another key factor that determines a star's colour is its temperature. As stars become hotter, the overall radiated energy increases, and the peak of the curve changes to shorter wavelengths. To put it another way, when a star heats up, the light it produces moves toward the blue end of the spectrum.</em>

4 0
2 years ago
Calculate the net force on particle q1. First, find the direction of the force particle q2 is exerting on particle q1. Is it pus
ValentinkaMS [17]

The net force on particle particle q1 is 13.06 N towards the left.

<h3>Force on q1 due to q2</h3>

F(12) = kq₁q₂/r₂

F(12) = (9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶)/(0.25²)

F(12) = -14.41 N  (towards left)

<h3>Force on q1 due to q3</h3>

F(13) = (9 x 10⁹ x 7.7 x 10⁻⁶ x 5.9 x 10⁻⁶)/(0.55²)

F(13) = 1.352 N (towards right)

<h3>Net force on q1</h3>

F(net) = 1.352 N - 14.41 N

F(net) = -13.06 N

Thus, the net force on particle particle q1 is 13.06 N towards the left.

Learn more about force here: brainly.com/question/12970081

#SPJ1

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