Answer:
Work done = 35467.278 J
Explanation:
Given:
Height of the cone = 4m
radius (r) of the cone = 1.2m
Density of the cone = 600kg/m³
Acceleration due to gravity, g = 9.8 m/s²
Now,
The total mass of the cone (m) = Density of the cone × volume of the cone
Volume of the cone = 
thus,
volume of the cone = 
= 6.03 m³
therefore, the mass of the cone = 600 Kg/m³ × 6.03 m³ = 3619.11 kg
The center of mass for the cone lies at the 
times the total height
thus,
center of mass lies at, h' = 
Now, the work gone (W) against gravity is given as:
W = mgh'
W = 3619.11kg × 9.8 m/s² × 1 = 35467.278 J
It is said to be concave
and convex is the one reflecting outward
9.1 basic since > 7
1.2 VERY acidic << 7
<span>5.7 acidic < 7
</span>
Answer:
Explanation:
The missing image of the figure slide is attached in below.
However, from the model, it is obvious that it is in equilibrium.
As a result, the relation of the force and the torque is said to be zero.
i.e.
and 
From the image, expressing the forces through the y-axis, we have:
Also, let the force 
be the pivot and computing the torque to determine 
:
Then:
For the force equation:
where:
Then:
For this case we have the following equation:
-16t + 8t + 8 = 0
The first thing we must do is rewrite the equation correctly.
We have then:
-16t ^ 2 + 8t + 8 = 0
Solving the polynomial we have:
t1 = -1/2
t2 = 1
We discard the negative root because we want to find the time.
Answer:
it takes for the object to reach the ground about:
t = 1 second
