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4 years ago

When is orange is the new black episodes come out

Physics

1 answer:

xenn [34]4 years ago

3 0

Some are out but will be on Netflix June 17

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Calculate the magnitude of the effort in the given

Otrada [13]

Moment = Force x Distance from pívot
500x0.5=2.5 x effort
250= 2.5 x effort
effort = 250/2.5= 100N

8 0

3 years ago

Deltas, like this one, are formed at the mouth of a river. They are formed by the ___________ of sediments, soil, sand, gravel,

adelina 88 [10]

Compression is the correct answer

7 0

4 years ago

Read 2 more answers

A uniform solid disk and a uniform hoop are placed side by side at the top of an incline of height h. If they are released from

svlad2 [7]

Answer:

) the uniform disk has a lower moment of inertia and arrives first.

Explanation:

(a) the uniform disk has a lower moment of inertia and arrives first.

(b) Let's say the disk has mass m and radius r, and

the hoop has mass M and radius R.

disk: initial E = PE = mgh

I = ½mr², so KE = ½mv² + ½Iω² = ½mv² + ½(½mr²)(v/r)² = (3/4)mv² = mgh

m cancels, leaving v² = 4gh / 3

hoop: initial E = Mgh

I = MR², so KE = ½MV² + ½(MR²)(V/R)² = MV² = Mgh

M cancels, leaving V² = gh

Vdisk = √(4gh/3) > Vhoop = √(gh)

3 0

3 years ago

I have an object that I want to know when it was made. I calculate that the object contains 0.12g of Iodine-131 but started with

Sav [38]

Answer: 71.72 days

Explanation:

This problem can be solved using the Radioactive Half Life Formula:

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=0.12 g$ is the final amount of Iodine-131

$A_{o}=60 g$ is the initial amount of Iodine-131

$t$ is the time elapsed

$h=8 days$ is the half life of Iodine-131

Knowing this, let's substitute the values and find $t$ from (1):

$0.12 g=(60 g)2^{\frac{-t}{8 days}}$ (2)

$\frac{0.12 g}{60g}=2^{\frac{-t}{8 days}}$ (3)

Applying natural logarithm in both sides:

$ln(\frac{0.12 g}{60g})=ln(2^{\frac{-t}{8 days}})$ (4)

$-6.21=-\frac{t}{8 days}ln(2)$ (5)

Finding $t$ :

$t=71.72 days$

7 0

4 years ago

a metal bal is held at rest H=65.0 cm above the floor. The ball is released with no initial velocity. How much time does it take

Fofino [41]

Answer:

Metal ball will take 0.364 seconds to reach floor.

Explanation:

Initial height from ground = 65 cm = 0.65 meter

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this the velocity of body in vertical direction = 0 m/s, acceleration =acceleration due to gravity = 9.8 $m/s^2$ , we need to calculate time when s = 0.65 meter.

Substituting

$0.65=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 0.364 seconds$

So it will take 0.364 seconds to reach floor.

5 0

4 years ago