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dolphi86 [110]
3 years ago
15

(NO LINKS) QUESTION BELOW

Mathematics
1 answer:
pshichka [43]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Subtract the exponents. 8-2=6 Therfore B. Sorry im in a rush.

If this was helpful, please give brainliest! It would help a lot!

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Which expression is equivalent to (5.4 x 1010) (3.3x1021)?
zmey [24]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
An eagle is flying at a height of 275 feet and climbing at a rate of 65 feet per second. The equation for the height of the bird
77julia77 [94]
The slope represents the how fast the bird is climbing and the Y intercept represents where the bird started to climb
7 0
3 years ago
Two equal groups of seedlings, and equal in height, were selected for an experiment. One group of seedlings was fed Fertilizer A
ser-zykov [4K]

Answer:

Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0

Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0

Here to test Fertilizer A height is greater than Fertilizer B

Two Sample T Test:

t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}

Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154

t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524

P value for Test Statistic of P(3.3524,26) = 0.0012

df = n1+n2-2 = 26

Critical value of P : t_{0.025,26}=2.05553

We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.

6 0
3 years ago
A simple random sample with n = 58 provided a sample mean of 24.5 and a sample standard deviation of 4.4. (Round your answers to
nasty-shy [4]

Answer: (23.53, 25.47)

Step-by-step explanation:

The confidence interval for population mean(when population standard deviation is unknown) is given by :-

\overline{x} \pm\ t^*\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n = sample size.

s = sample standard deviation.

t* = Critical value.

Given : \overline{x}=24.5

s= 4.4

Confidence level = 90% =0.090

Significance level = \alpha=1-0.90=0.10

Sample size : n= 58

Degree of freedom : df= n-1= 57

Using t-distribution table , the critical value :

t_{\alpha/2,\ df}= t_{0.05,\ 57}=1.6720

Then, the confidence interval will be :-

24.5 \pm\ (1.6720)\dfrac{4.4}{\sqrt{58}}

24.5 \pm\ (1.6720)\dfrac{4.4}{7.61577310586}

24.5 \pm\ 0.965995165263\approx24.5\pm0.97\\\\=(24.5-0.97,\ 24.5+0.97)\\\\=(23.53,\ 25.47)

Hence, a 90% confidence interval for the population mean = (23.53, 25.47)

6 0
4 years ago
Part A) Julio makes a scale drawing of the kitchen floor to determine how many square feet of flooring he needs to buy . The sca
serg [7]
Part A) 
we know that
<span>scale ---------->  inch/4 feet=0.25 in/ft

</span>[scale]=[scale drawing]/[actual]
[actual]=[scale drawing]/[scale]

for <span>length --------> 4 1/2 in ---------> 4.5 in  (</span>scale drawing)
[actual]=[4.5]/[0.25]=18 ft

for <span>width ---------> 3 3/8 in</span> ---> (3*8+3)/8 ---> 27/8 in  (scale drawing)
[actual]=[27/8]/[0.25]=13.5 ft

the answer part A is
length actual <span>kitchen floor is 18 ft
</span>width actual kitchen floor is 13.5 ft

Part B)  
the area of one square in the actual=(1/2)*(1/2)=0.25 ft²
total area gray tiles=0.25*14=3.5 ft²
total area white tiles=0.25*10=2.5 ft²

find <span>how many tiles 2 in by 2 in of each color will he need
1ft</span>²-------------> 144 in²
gray tiles
3.5 ft²---------------> 3.5*144=504 in²
[tiles 2 in by 2 in gray]=504/(2*2)=126 gray tiles 

white tiles
2.5 ft²---------------> 2.5*144=360 in²
[tiles 2 in by 2 in white]=360/(2*2)=90 white tiles 

the answer Part B) is
126 gray tiles
90 white tiles 



6 0
4 years ago
Read 2 more answers
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