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zhenek [66]
3 years ago
6

two sections of a garden are shaped like and then tickle triangle the base of each triangle is 50 feet and the other two that ar

e each X feet long is the combined perimeter of both Garden is 242 feet find the value of x
Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0
A triangle can only equal 180 so you take 180-50 and get 130 then you divide 130 by 2 your answer is 65      X =65
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OLEGan [10]

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(x +y)^5<br> Complete the polynomial operation
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Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

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a=x,\:\:b=y

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so expanding summation

=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5

solving

\frac{5!}{0!\left(5-0\right)!}x^5y^0

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=1\cdot \:1\cdot \:x^5

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also solving

=\frac{5!}{1!\left(5-1\right)!}x^4y

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=\frac{5}{1!}x^4y

=\frac{5x^4y}{1}

=\frac{5x^4y}{1}

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similarly, the result of the remaining terms can be solved such as

\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2

\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3

\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4

\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5

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=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5

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8 0
3 years ago
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