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zalisa [80]
3 years ago
14

The mean age at first marriage for respondents in a survey is 23.33, with a standard deviation of 6.13. The Z score associated w

ith a particular age at first marriage is 0.35. If the proportion of the area between this particular age at first marriage and the mean is 0.14, what proportion of respondents experienced their first marriage earlier than this age?
Mathematics
1 answer:
Anestetic [448]3 years ago
3 0

Answer:

42.48

Step-by-step explanation:

I don't know how to explain

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A professor gives two types of quizzes, objective and recall. He is planning to give at least 15
nadya68 [22]

Answer:

x₁ = 20     x₂ = 0

z (min) = 20

Step-by-step explanation:

According to the problem statement:

Let´s call

Objective quiz =  x₁               Recall quiz =  x₂

First constraint

Quantity of quizzes at least 15

x₁  +  x₂  ≥ 15

Second constraint:

Preparation time   at least 300 minutes, then

15*x₁  +  30*x₂  ≥   300

Third constraint

Average score  at least  85 points

7*x₁  +  5*x₂   ≥  85

General constraint x₁ ≥ 0   x₂ ≥ 0

Objective function z is:

z = 1* x₁ + 1,5*x₂     to minimize

The model:

z = x₁  + 1,5x₂      to minimize

Subject to

x₁  +  x₂  ≥ 15

15*x₁  +  30*x₂  ≥   300

7*x₁  +  5*x₂   ≥  85

Using Atozmax (online solver) we find

x₁ = 20     x₂ = 0

z (min) = 20

5 0
3 years ago
The manager of a company uses the function shown to model the company’s daily profit based on the price of a product in dollars,
just olya [345]

Answer: 1) The minimum price, in dollars, to avoid a loss = 22,

2) the maximum price in dollars , to avoid a loss = 53,

3) The price that results the maximum profit = 37.5 dollars

Step-by-step explanation:

Since the given function that shows the total profit,

f(x) = (x-22)(53-x)

Where x is the price of the product.

Since for avoiding the loss,

f(x) \geq 0,

⇒ (x-22)(53-x)\geq 0

If (x-22)\geq 0 \implies x\geq 22

If 53 - x \geq 0 \implies 53 \geq x

Thus, 53 ≥ x ≥ 22,

Therefore, the minimum price to avoid the loss = $ 22

And, the minimum price to avoid the loss = $ 53

f'(x) =\frac{d}{dx}[(x-22)(53-x)] = (x-22)\frac{d}{dx} (53-x)+(53-x) \frac{d}{dx}(x-22)

⇒ f'(x) = - (x-22)+(53-x) = -x+22+53-x =-2x+75

Now, For maximum or minimum,

f'(x) = 0,

⇒ -2x+75 = 0

⇒ -2x = -75

⇒ x = 37.5

f''(x) = \frac{d}{dx}(-2x+75)=-1

For x = 37.5, f''(x) is negative,

Thus, For the price of $ 37.5 dollars the company has the greatest profit.



4 0
3 years ago
Which of the follwing is not a pythagorean triple 10,16 19<br>8,15,17<br>16,63,65<br>11,60,61​
zaharov [31]

Answer:

Step-by-step explanation:

4 0
3 years ago
Coach Williams bought trophies for his players at the end of the season. Each trophy is packed in a cube-shaped box that has a v
Diano4ka-milaya [45]

Answer:

The volume of the cart will be 24 ft^3

Step-by-step explanation:

The first thing we need to calculate for this question is the number of boxes that fill the entire cart.

A layer of boxes consists of 8 boxes.

The cart holds a maximum of 3 layers of boxes.

So, the total number of boxes held by the cart are:

Total boxes = number of layers * boxes per layer

Total boxes = 3 * 8

Total boxes = 24

Since each box has a volume of one cubic foot, the total volume of the cart will be:

Volume of cart = number of boxes * volume of each box

Volume of cart = 24 * 1

Volume of cart = 24 ft^3

5 0
3 years ago
PLS HELP NO LINKS
Archy [21]

Answer:

3.6 cubic feet

Step-by-step explanation:

The volume of the box is simply the product of the 3 sides. so 2ft \times 1.5ft \times 1.2 ft = 3.6 ft^3

4 0
2 years ago
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