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sveta [45]
2 years ago
11

A professor gives two types of quizzes, objective and recall. He is planning to give at least 15

Mathematics
1 answer:
nadya68 [22]2 years ago
5 0

Answer:

x₁ = 20     x₂ = 0

z (min) = 20

Step-by-step explanation:

According to the problem statement:

Let´s call

Objective quiz =  x₁               Recall quiz =  x₂

First constraint

Quantity of quizzes at least 15

x₁  +  x₂  ≥ 15

Second constraint:

Preparation time   at least 300 minutes, then

15*x₁  +  30*x₂  ≥   300

Third constraint

Average score  at least  85 points

7*x₁  +  5*x₂   ≥  85

General constraint x₁ ≥ 0   x₂ ≥ 0

Objective function z is:

z = 1* x₁ + 1,5*x₂     to minimize

The model:

z = x₁  + 1,5x₂      to minimize

Subject to

x₁  +  x₂  ≥ 15

15*x₁  +  30*x₂  ≥   300

7*x₁  +  5*x₂   ≥  85

Using Atozmax (online solver) we find

x₁ = 20     x₂ = 0

z (min) = 20

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In the number 3.072 the digit 7 is in the ? place and the digit 2 is in the ? place.​
notka56 [123]

Answer:

7= Hundredths

2=Thousandths

8 0
3 years ago
A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in
Oksi-84 [34.3K]

Answer: The concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

                               Compound X             Compound Y

272                               16400                            3870

327                                3990                             6420

So, our equations becomes

16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191

By solving these two equations, we get that

C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}

Hence, the concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

5 0
3 years ago
Will give brainliest!
fiasKO [112]
Let's give some distances
100 up 100 flat 100 down meters
then return 100 up 100 flat 100 down


time required (distance/rate = time ) 200/100 + 200/120 + 200 / 150 = 5 hr

distance 600


distance / time = average speed = 600/5 = 120 m/s
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2 years ago
In 1989 a postage stamp cost $.25. In 1999 a postage stamp cost $.33. Find the average rate of
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Answer:

0.33-0.25= 0.08

then 1999-1989= 10

lastly 0.008

Step-by-step explanation: so the  average rate of

change in postage in<em><u> cents</u></em> per year. is 0.8 of a cent. or 0.008 of a dollar.

7 0
2 years ago
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The original price of a book is x dollars. The book is sold for 10% discount. After that, the increased by 25%
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Answer:

assume X dollar is $100

If so then,

$100-10% =$90

Thus,

$90x125%=$112.5

4 0
1 year ago
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