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Alexeev081 [22]
4 years ago
14

There are 94 suitcases in number one cargo bin. There are two cargo bins to be loaded on the airplane. The second bin contains 2

14 suitcases and the third 103 suitcases. If all three of these cargo bins are loaded onto the 747 airplane, how many total suitcases will be in the cargo area?
Mathematics
1 answer:
Lera25 [3.4K]4 years ago
8 0
To find the answer for your question you have to add the number of suitcases in the cargo bins, because all cargo bins are been loaded to the airplane.
94+214+103= 144

so your answer is 144 suitcases  
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Compute a value for y that satisfies the equation below. <br><br> -3y - 12 = -4
lesantik [10]
First, add 12 to both sides of the equation,
                            -3y - 12 + 12 = -4 + 12
                                -3y = 8
Then, divide both the left hand and right hand sides of the equation by -3
                                   (-3y) / -3 = 8/-3
The value of y is therefore,
                                         y = -8/3
5 0
4 years ago
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Naddika [18.5K]
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7 0
3 years ago
Definition: A fraction a/b is reduced if a and b are relatively prime.
Mariulka [41]

Answer:

it is true

Step-by-step explanation:

We can demonstrate this by contradiction.

First choosing a random rational and assuming that exist two ways to represent this rational. Call that rational x, a, b and a', b ' the couples of relatively prime to express x.

Then we have

x=x\\\frac{a}{b}=\frac{a'}{b'}

Isolating a:

a=\frac{a'b}{b'}

a is an integer and a' is a relatively prime with b', for this reason b has to be a factor of b'. Suppose this factorization b'=nb, replacing it:

a=\frac{a'nb'}{b'}=a'n

But now we have that n is a factor of a and is a factor of b, it means that a and b are not relatively prime, that is a contradiction with our premises. The sentence is true.

And referring to the positive denominator. If we want to express a positive rational the denominator and numerator will be both positive and if is a negative one we choose a positive denominator and a negative numerator.

3 0
3 years ago
Pls answer I need help and I need it now pls answer
zmey [24]

Answer:

4+(x*4)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Help with 5b please . thank you.​
Allushta [10]

Answer:

See explanation

Step-by-step explanation:

We are given f(x)=ln(1+x)-x+(1/2)x^2.

We are first ask to differentiate this.

We will need chain rule for first term and power rule for all three terms.

f'(x)=(1+x)'/(1+x)-(1)+(1/2)×2x

f'(x)=(0+1)/(1+x)-(1)+x

f'(x)=1/(1+x)-(1)+x

We are then ask to prove if x is positive then f is positive.

I'm thinking they want us to use the derivative part in our answer.

Let's look at the critical numbers.

f' is undefined at x=-1 and it also makes f undefined.

Let's see if we can find when expression is 0.

1/(1+x)-(1)+x=0

Find common denominator:

1/(1+x)-(1+x)/(1+x)+x(1+x)/(1+x)=0

(1-1-x+x+x^2)/(1+x)=0

A fraction can only be zero when it's numerator is.

Simplify numerator equal 0:

x^2=0

This happens at x=0.

This means the expression,f, is increasing or decreasing after x=0. Let's found out what's happening there. f'(1)=1/(1+1)-(1)+1=1/2 which means after x=0, f is increasing since f'>0 after x=0.

So we should see increasing values of f when we up the value for x after 0.

Plugging in 0 gives: f(0)=ln(1+0)-0+(1/2)0^2=0.

So any value f, after this x=0, should be higher than 0 since f(0)=0 and f' told us f in increasing after x equals 0.

8 0
3 years ago
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