Hi GlaxyCraft4991,
Solution:
−12x − 0.4 > 0.2 (36.5x + 80) − 55
−12x − 0.4 > 7.3x − 39
−12x − 0.4 − 7.3x > 7.3x − 39 − 7.3x
−19.3x − 0.4 > −39
−19.3x − 0.4 + 0.4 > −39 + 0.4
−19.3x > −38.6
−19.3x/19.3 > −38.6/19.3
x < 2
Correct Answer:
x < 2
<span>Equivalent ratios are ratios that name the same comparison. Meanwhile, equivalent fractions </span><span>are fractions that name the same amount or part. Equivalent ratios and equivalent fractions are similar in that the two quantities refer to ratios and fractions that ultimately have the same value but are expressed in a different way. For example, 48/64 is equivalent to 72/96, both have the value of 3/4. </span>
G^−m ÷ g^n
1st g^−m=1/g^m, hence g^−m ÷ g^n = (1/g^m) /(g^n)==> 1/(g^m)(g^(n)
==> 1/(g^m+n) or g^(-m-n)
Let
x-------> the number of dinner
y-------> the number of lunch
we know that
-------> equation A
------> equation B
Substitute equation B in equation A
![8[y]+5y \leq 42](https://tex.z-dn.net/?f=8%5By%5D%2B5y%20%5Cleq%2042)
so
the greatest number of lunch is 
Hence
the greatest number of dinner is 
therefore
the greatest number of meals is
<u>the answer is</u>
