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stepladder [879]
3 years ago
13

Help me please i have a 63 in math :( if you can then please add my insta so you can help. it is manny._.memes2.0_

Mathematics
1 answer:
DerKrebs [107]3 years ago
8 0

Answer:I believe this is a demonstartion of the communitive property the equation backwards is the right5 awnser

Step-by-step explanation:

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If the length of rectangle is x + 4 and the width is 3x - 5 what is the perimeter?
statuscvo [17]

Answer:

8x-2

Step-by-step explanation:

l = x+4

w = 3x-5

The perimeter is

P =2(l+w)

   = 2(x+4+3x-5)

Combine like terms

   = 2(4x-1)

Distribute

   = 8x-2

6 0
3 years ago
Read 2 more answers
there are 500 hundred pages. if the book has 25 chapters and each chapter is 20 pages long. what is the chance that of randomly
nataly862011 [7]
20/500
0.04 of a chance
because 1 chapter has 20 pages and the book has 500
so the chance of you flipping to chapter 12 out of 500 pages is 4% of a chance
6 0
3 years ago
Please help me with this.
-Dominant- [34]

Answer:

3

Step-by-step explanation:

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

3^4 +9^2÷3^3-9^2

81+81÷27-81

81+3-81

3

5 0
3 years ago
What is the ratio 18 to 27 written as a fraction in lowest terms?
Studentka2010 [4]
18:27=\dfrac{18}{27}=\dfrac{18:9}{27:9}=\dfrac{2}{3}=2:3
7 0
4 years ago
URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.
dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

\large \boxed{ {tan}^{2}  \theta  =  {sec}^{2}   \theta - 1}

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

\large{ {tan}^{2}  \theta =  {( -  \frac{3}{2}) }^{2}  - 1} \\   \large{ {tan}^{2}  \theta =   \frac{9}{4}  - 1} \\   \large{ {tan}^{2}  \theta = \frac{9}{4}   -  \frac{4}{4} \longrightarrow  \frac{5}{4}  } \\  \large{tan \theta =  \frac{ \sqrt{5} }{ \sqrt{4} } } \\  \large \boxed{tan \theta =  \frac{ \sqrt{5} }{2} }

Since tan is negative in the second quadrant. Hence,

\large{ \cancel{ tan \theta  =  \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta =  -  \frac{ \sqrt{5} }{2} }}

Answer

  • tan = -√5/2
3 0
3 years ago
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