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3 years ago

6

Time for reading solving inequalities with decimals

1 answer:

PolarNik [594]3 years ago

6 0

<span><span>The velocity of an object fired directly upward is given by <span>V = 80 – 32t</span><span>, where </span>t<span> is in seconds.

When will the velocity be between </span>32<span>and </span>64<span> feet per second?</span></span><span>I will set up the compound inequality, and then solve for </span>t:</span><span><span>    32 < 80 – 32t < 64</span> <span>
    32 – 80 < 80 – 80 – 32t < 64 – 80</span> <span>
    –48 < –32t < –16</span><span>    –48 /<span> –32</span></span><span>  >  </span><span><span>–32t</span> /<span> –32</span>  </span><span>>  </span><span>–16 /<span> –32</span></span><span>    1.5 > t > 0.5</span></span>

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i will give brainliest.The product of 5 and the sum of 12 and a certain number is 10. What is the number

rjkz [21]

Answer: x=-10

Step-by-step explanation:

5*(12+x)=10

Distribute

60+5x=10

Subtract(60)

5x=-50

x=-10

<em>Hope it helps <3</em>

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4 years ago

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Allushta [10]

Answer:

(2x+1)(x+2)

Step-by-step explanation:

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3 years ago

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rodikova [14]

Answer: 54 stitches

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3 years ago

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9966 [12]

Answer:

A. 3.0 m/s

Step-by-step explanation:

Based on the graph,

velocity = Area of the graph

$v = \frac{y1 - y2}{x1 - x2}$

(y : position and x : time)

Let y1 = 2m and y2 = 14m,

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= 3.0 m/s

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3 years ago

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let a = (a1, a2) and b = (b1, b2) and c = (c1,c2) be three non zero vectors. if a1b2 - a2b1 is not equal to 0. then show three a

Ksenya-84 [330]

Consider the contrapositive of the statement you want to prove.

The contrapositive of the logical statement

<em>p</em> ⇒ <em>q</em>

is

¬<em>q</em> ⇒ ¬<em>p</em>

In this case, the contrapositive claims that

"If there are no scalars <em>α</em> and <em>β</em> such that <em>c</em> = <em>α</em><em>a</em> + <em>β</em><em>b</em>, then <em>a₁b₂</em> - <em>a₂b₁</em> = 0."

The first equation is captured by a system of linear equations,

$\begin{cases}c_1 = \alpha a_1 + \beta b_1\\ c_2 = \alpha a_2 + \beta b_2\end{cases}$

or in matrix form,

$\begin{pmatrix}c_1\\c_2\end{pmatrix} = \begin{pmatrix}a_1&b_1\\a_2&b_2\end{pmatrix}\begin{pmatrix}\alpha\\\beta\end{pmatrix}$

If this system has no solution, then the coefficient matrix on the right side must be singular and its determinant would be

$\begin{vmatrix}a_1&b_1\\a_2&b_2\end{vmatrix} = a_1b_2-a_2b_1 = 0$

and this is what we wanted to prove. QED

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