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gladu [14]
2 years ago
6

Time for reading solving inequalities with decimals

Mathematics
1 answer:
PolarNik [594]2 years ago
6 0
<span><span>The velocity of an object fired directly upward is given by <span>V = 80 – 32t</span><span>, where </span>t<span> is in seconds. 

When will the velocity be between </span>32<span>and </span>64<span> feet per second?</span></span><span>I will set up the compound inequality, and then solve for </span>t:</span><span><span>    32 < 80 – 32t < 64</span> <span>
    32 – 80 < 80 – 80 – 32t < 64 – 80</span> <span>
    –48 < –32t < –16</span><span>    –48 /<span> –32</span></span><span>  >  </span><span><span>–32t</span> /<span> –32</span>  </span><span>>  </span><span>–16 /<span> –32</span></span><span>    1.5 > t > 0.5</span></span>
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PLEASE HELP ME QUICKLY!!
OLEGan [10]
Your Answer is correct, because for every rate of change the x-value (-1) is decreasing, and the rate of change f(x)-value (-3) is also decreasing. This gives you a -1/-3 rate of change (slope). Two negatives make a positive therefore the is at a constant rate of change (slope) of 1/3.

Keep in mind unfortunately I am not 100% sure, but this is what I think. Hope this helps a little!
3 0
3 years ago
Given the following geometric sequence, find the common ratio. {0.45, 0.9, 1.8, ...}
erma4kov [3.2K]
0.45 times what=0.90?
seems to be 2
for
a_n and a_{n+1}, (1 term and the next)
common ratio=\frac{a_n}{a_{n+1}}
0.45 and 0.9
0.9/0.45=2
common ratio is 2
6 0
3 years ago
Read 2 more answers
Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h
vladimir2022 [97]

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

  • 1 - 0.12 = 0.88
  • 0.88 ^ 17 = 0.1138
  • 0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

  • 0.88 ^ 18 - 0.12 ^ 2 = X
  • 0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

  • 0.12 ^ 6 x 0.88 ^ 12 = X
  • 0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534

3 0
2 years ago
Given the function f(x) = 2/3 * x - 5 , evaluate f(9)
ch4aika [34]

Answer:

1

Step-by-step explanation:

5 0
3 years ago
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Please help with my math work !<br> due tomorrow morning
Y_Kistochka [10]

Answer:

y=2x+6

Hope This Helps! :)

3 0
1 year ago
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