Answer:
Therefore the correct assembling is
3.∠DAC ≅ ∠BCA 3. Alternate interior Angles are Equal as AD || BC.
Step-by-step explanation:
Given:
AD ≅ BC and AD || BC
To Prove:
ABCD is a Parallelogram
Proof:
Alternate Interior Angles Theorem :
"When two parallel lines are cut by a transversal , the resulting alternate interior angles are congruent.
Here AD || BC and the transversal is AC
Statement Reasons
1. AD ≅ BC . 1. Given
2. AD || BC 2. Given
3.∠DAC ≅ ∠BCA 3. Alternate interior Angles are Equal as AD || BC.
Therefore the correct assembling is
3.∠DAC ≅ ∠BCA 3. Alternate interior Angles are Equal as AD || BC.
Hey there!
Which is the prime factorization of 40?
Option A.
2 * 5
= 2 + 2 + 2 + 2 + 2
= 4 + 4 + 2
= 8 + 2
= 10
Option B.
2^3 * 5
= 2 * 2 * 2 * 5
= 4 * 2 * 5
= 8 * 5
= 40
Option C.
2 * 53
= 53 * 2
= 53 + 53
= 106
2 * 3 * 5
= 6 * 5
= 6 + 6 + 6 + 6 + 6
= 12 + 12 + 6
= 24 + 6
= 30
Therefore, your answer is:
Option B. 2^3 * 5
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
The intersection of the two sets is the list of members that appear in both sets. That is {3}.
Your statement is FALSE.
Answer:

Step-by-step explanation:
The surface area of a square pyramid is the sum of the area of the squared base + 4 times the area of each triangular face, therefore:

where:
is the area of the base, where
L is the length of the base
is the area of each triangular face, where
h is the height of the face
Substituting,

For the model in this problem,
L = 12
h = 8
Therefore, the surface area here is:
