Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
To solve this I'm going to split the middle term.
First multiply the first and last terms:
24x^2
So find two numbers that multiply to 24x^2 and add to 11x.
This would be 3x and 8x
Rewrite the problem as
4x^2+3x+8x+6
Take the first and 3rd and 2nd and 4th terms
4x^2 and 8x
and
3x and 6
Factor by grouping
Take out a 4x for the first group to get 4x(x+2)
Take out a 3 for the 2nd group to get 3(x+2)
Rewrite as (4x+3)(x+2)
Hope this helps.
Answer is 18
I found it by multiplying 20 by .90
Answer:
15 ft
Step-by-step explanation:
In a parallelogram the diagonals bisects each other
So WC= CY
solve the equation for x
Subtract x from both sides
Now we add 7 on both sides
x=11
Now we need to find CY

Plug in 11 for x

The area of a polygon equals
area = circumradius² * number of sides * sin (360 / # of sides) / 2
area = 77² * 20 * sin (360 / 20) / 2
area = 77² * 20 * sin (18) / 2
area = 118,580 * 0.30902 / 2
area =
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<span>
<span>
36,643.59
</span>
</span>
</span>
/ 2
area =
18,321.8 square millimeters