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Ira Lisetskai [31]
3 years ago
11

What do you do to solve a problem that has just a negative in front of the parentheses?

Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0
If there is a negative symbol in front of the parentheses, it indicates that you must multiply what's inside the parentheses by -1 (if you only have a negative symbol in front of it) or multiply it by whatever negative number is provided.
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It took Everly 55 minutes to run a 10-kilometer race last weekend. If you know that 1 kilometer equals 0.621 mile, how many minu
slega [8]
\bf \cfrac{10km}{55mins}\cdot \cfrac{0.621miles}{1km}\implies \cfrac{62.1miles}{55mins}\approx 1.12909909\approx \boxed{1.13\frac{miles}{mins}}
5 0
3 years ago
An airplane is traveling at an altitude of 30,000 feet
Murljashka [212]

Answer:

10 minutes

Step-by-step explanation:

First, find how much higher the airplane has to travel:

35,000 - 30,000

= 5,000

To fine how long it will take, divide 5000 by 500

5000/500

= 10

So, it will take 10 minutes to get above 35,000 feet

5 0
3 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
Which subset(s) of numbers does 8 2/3<br> belong to?
Tems11 [23]

Answer:

Rational number/integer

7 0
3 years ago
Use the information provided to write the standard form eqaution of each parabola. y=2(x+2)^2+9
gtnhenbr [62]

Answer:

y = 2 x 2 + 8 x + 17

Step-by-step explanation:


4 0
3 years ago
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