Step-by-step explanation:
5p + 6p -10 = -29 - 8p
11p - 10 = -29 - 8p
+10 +10 +8p
+8p = -19
19p=-19
p=-1
Answer:
300=10x+20y
Step-by-step explanation:
You are trying to get the sales to equal 300 so the 10x and 20y added together will get you 300
The probability of loss is
1 - 0.2 - 0.1 = 0.7
Answer:
(f⋅g)(x)![= x^7 + 9x^4 - 9x^3 -81](https://tex.z-dn.net/?f=%20%3D%20x%5E7%20%2B%209x%5E4%20-%209x%5E3%20-81)
![(f - g)(x) = x^3 - 6x^2 + 18x + 6x - 10](https://tex.z-dn.net/?f=%28f%20-%20g%29%28x%29%20%3D%20x%5E3%20-%206x%5E2%20%2B%2018x%20%2B%206x%20-%2010)
Step-by-step explanation:
For the first part of the question we have two functions
![f(x) = x^4 -9](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E4%20-9)
![g(x) = x^3 + 9](https://tex.z-dn.net/?f=g%28x%29%20%3D%20x%5E3%20%2B%209)
If the expression refers to the multiplication of f and g, then:
(f⋅g)(x)![= f (x)g(x)](https://tex.z-dn.net/?f=%20%3D%20f%20%28x%29g%28x%29)
So we multiply the function f(x) with the function g(x)
(f⋅g)(x)![= (x^4 - 9)(x^3 + 9)](https://tex.z-dn.net/?f=%20%3D%20%28x%5E4%20-%209%29%28x%5E3%20%2B%209%29)
(f⋅g)(x)![= x^7 + 9x^4 - 9x^3 -81](https://tex.z-dn.net/?f=%20%3D%20x%5E7%20%2B%209x%5E4%20-%209x%5E3%20-81)
For the second part we have the functions:
![f(x) = x^3 -2x^2 + 12x - 6\\\\g(x) = 4x^2 - 6x + 4](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E3%20-2x%5E2%20%2B%2012x%20-%206%5C%5C%5C%5Cg%28x%29%20%3D%204x%5E2%20-%206x%20%2B%204)
We wish to find (f - g) (x). We know that
![(f - g)(x) = f(x) - g(x)\\\\(f - g)(x) = x^3 - 2x^2 + 12x - 6 - [4x^2 - 6x + 4]\\\\(f - g)(x) = x^3 - 2x^2 + 12x - 6 -4x^2 + 6x - 4](https://tex.z-dn.net/?f=%28f%20-%20g%29%28x%29%20%3D%20f%28x%29%20-%20g%28x%29%5C%5C%5C%5C%28f%20-%20g%29%28x%29%20%3D%20x%5E3%20-%202x%5E2%20%2B%2012x%20-%206%20-%20%5B4x%5E2%20-%206x%20%2B%204%5D%5C%5C%5C%5C%28f%20-%20g%29%28x%29%20%3D%20x%5E3%20-%202x%5E2%20%2B%2012x%20-%206%20-4x%5E2%20%2B%206x%20-%204)
![(f - g)(x) = x^3 - 6x^2 + 18x + 6x - 10](https://tex.z-dn.net/?f=%28f%20-%20g%29%28x%29%20%3D%20x%5E3%20-%206x%5E2%20%2B%2018x%20%2B%206x%20-%2010)