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Simora [160]
2 years ago
9

HELPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Shalnov [3]2 years ago
7 0
I’m pretty sure it would be C= 81.64
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Two skaters are practicing at the same time on the same rink. A coordinate grid is superimposed on the ice. One skater follows t
myrzilka [38]

Answer:

The skaters will collide at the points;

(2,28) and (4,24)

Step-by-step explanation:

The points they might collide will be the points when both y are equal;

-2x + 32 = -2x^2 + 18x

2x^2 -18x -2x + 32 = 0

2x^2 -20x + 32 = 0

2x^2 - 16x - 4x + 32 = 0

2x(x -8) -4( x -8) = 0

(2x -4)(x -8) = 0

2x = 4 or x = 8

x = 4/2 or x = 8

hence; x = 2 or 8

Now let’s get the y value

at x = 2, just substitute into any of the 2

y = -2x + 32

y = -2(2) + 32

y = -4 + 32 = 28

at x = 4

y = -2(4) + 32

y = -8 + 32

y = 24

The points that they will collide are;

(2,28) and (4,24)

4 0
3 years ago
Solve for x. <br> 2(x-2)= 6x + 2 -2(-2x - 4)
Lena [83]

Answer:-7/4

Step-by-step explanation:

2(x-2)=6x+2-2(-2x-4)

Open brackets

2x-4=6x+2+4x+8

Collect like terms

-4-2-8=6x+4x-2x

-14=8x

Divide both sides by 8

-14/8=8x/8

-7/4=x

x=-7/4

4 0
3 years ago
Factor using the identity: a3 + b3 = (a + b)(a2 – ab + b2) 8z3 + 27
vivado [14]

Answer:  this is our required factor i.e.

8z^3+27=(2z+3)(4z^2-6z+9)

Explanation:

Since we have given that

8z^3+27

As we know the identity , which says that

a^3+b^3=(a+b)(a^2-ab+b^2)

So, we can use this here ,

8z^3+27=(2z)^3+3^3\\\\=(2z+3)((2z)^2-2z\times 3+3^2)\\\\=(2z+3)(4z^2-6z+9)

Hence this is our required factor i.e.

8z^3+27=(2z+3)(4z^2-6z+9)


7 0
3 years ago
Read 2 more answers
dennis ran a mile in 593.7 seconds.martina ran a mile in 573.36 seconds. what was the difference in their running times? A-5.14
Svetlanka [38]

subtract them

593.7-573.36 = 20.34seconds

 so c is the answer


8 0
3 years ago
Read 2 more answers
Verify the identity by transforming the left-hand side into the right-hand side.
qaws [65]
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1

Starting with the left:  Note that  cos²θ + </span><span>sin²θ = 1.
In the same way:    </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore                cos²3θ  = 1 - <span>sin²3θ
</span> From the top:  (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ

=  2/<span>sin² 3θ - 1;        But 1/</span><span>sinθ = csc</span><span>θ,  Similarly  </span>1/sin3θ = csc3θ

= 2 *(1/sin<span>3θ)²  - 1</span>
= 2csc²3θ  - 1.        Therefore  LHS = RHS.  QED.

8 0
3 years ago
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