Answer:
The skaters will collide at the points;
(2,28) and (4,24)
Step-by-step explanation:
The points they might collide will be the points when both y are equal;
-2x + 32 = -2x^2 + 18x
2x^2 -18x -2x + 32 = 0
2x^2 -20x + 32 = 0
2x^2 - 16x - 4x + 32 = 0
2x(x -8) -4( x -8) = 0
(2x -4)(x -8) = 0
2x = 4 or x = 8
x = 4/2 or x = 8
hence; x = 2 or 8
Now let’s get the y value
at x = 2, just substitute into any of the 2
y = -2x + 32
y = -2(2) + 32
y = -4 + 32 = 28
at x = 4
y = -2(4) + 32
y = -8 + 32
y = 24
The points that they will collide are;
(2,28) and (4,24)
Answer:-7/4
Step-by-step explanation:
2(x-2)=6x+2-2(-2x-4)
Open brackets
2x-4=6x+2+4x+8
Collect like terms
-4-2-8=6x+4x-2x
-14=8x
Divide both sides by 8
-14/8=8x/8
-7/4=x
x=-7/4
Answer: this is our required factor i.e.
Explanation:
Since we have given that
As we know the identity , which says that
So, we can use this here ,
Hence this is our required factor i.e.
subtract them
593.7-573.36 = 20.34seconds
so c is the answer
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1
Starting with the left: Note that cos²θ + </span><span>sin²θ = 1.
In the same way: </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore cos²3θ = 1 - <span>sin²3θ
</span> From the top: (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ
= 2/<span>sin² 3θ - 1; But 1/</span><span>sinθ = csc</span><span>θ, Similarly </span>1/sin3θ = csc3θ
= 2 *(1/sin<span>3θ)² - 1</span>
= 2csc²3θ - 1. Therefore LHS = RHS. QED.
