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Simora [160]
3 years ago
9

HELPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Shalnov [3]3 years ago
7 0
I’m pretty sure it would be C= 81.64
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What is the surface area of the monument
Semmy [17]

Answer:

660

Step-by-step explanation:

ok this one is a little more tricky

20*5=100 do not double this one

20*12=240 do not double this one

20*13=260 do not double this one

remember the area of a triangle is A=1/2l*w

plug in the values

A=1/2(5)(12)

A=30 you have to double this one because there is two of them

60

now you must add up all your values

100+240+260+60=660

i hope i am not wrong... but hope it helps!

3 0
3 years ago
Sin 2x + tan 2x = 4tan/ 1- tan^4 prove that
nalin [4]
\dfrac{4\tan x}{1-\tan^4x}=\dfrac{4\tan x}{(1-\tan^2x)(1+\tan^2x)}
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=\dfrac{4\tan x\cos^2x}{2-\sec^2x}
=\dfrac{4\sin x\cos x}{2-\sec^2x}
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=2\tan2x\left(\dfrac{1+\cos2x}2\right)
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7 0
3 years ago
Urgent I’ll give brainlist
Jobisdone [24]

Answer:

I think A

Step-by-step explanation:

Can you mark me brainliest because I am almost to level ace!

4 0
3 years ago
Read 2 more answers
Find value of P and Q
ch4aika [34]

Answer:

P= 6 \frac{1}{7}\\\\Q = 4 \frac{2}{7}

Step-by-step Explanation

\frac{5 + 3 \sqrt{2} }{5 - 3 \sqrt{2} }  = P+Q\sqrt 2 \\  \\  \frac{(5 + 3 \sqrt{2}) }{(5 - 3 \sqrt{2}) }  \times  \frac{(5 + 3 \sqrt{2}) }{(5   +  3 \sqrt{2} )} = P+Q\sqrt 2 \\  \\  \frac{ {(5 + 3 \sqrt{2} )}^{2} }{ {(5)}^{2}  - (3 \sqrt{2})^{2}  }  = P+Q\sqrt 2 \\  \\ \frac{ {5}^{2} +  {(3 \sqrt{2} )^{2}  + 2.5.3 \sqrt{2} } }{25 - 9 \times 2} = P+Q\sqrt 2 \\  \\\frac{ 25 + 18  + 30 \sqrt{2}  }{25 - 18} = P+Q\sqrt 2 \\  \\\frac{ 43  + 30 \sqrt{2}  }{7} = P+Q\sqrt 2 \\  \\ \frac{43}{7}  +  \frac{30 }{7} \sqrt{2}  = P+Q\sqrt 2 \\  \\ equating \: like \: terms \: on \: both \: sides \\  \\ P =  \frac{43}{7}   \\  \\ \huge \red { \boxed{ P= 6 \frac{1}{7}}}  \\  \\ Q =  \frac{30}{7}  \\  \\ \huge  \orange { \boxed{ Q = 4 \frac{2}{7} }}

4 0
3 years ago
Please help with this one kinda lost in it Thank you
aleksklad [387]
The answer is c.
i hope this helped!
6 0
3 years ago
Read 2 more answers
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