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Contact [7]
3 years ago
5

A rain gutter is to be constructed from a metal sheet of width 48 cm by bending up one-third of the sheet on each side through a

n angle θ.
Show that the cross-sectional area of the gutter is modeled by the function
A(θ) = 256 sin(θ) + 256 sin(θ) cos(θ).

For what angle θ is the largest cross-sectional area achieved?

Mathematics
1 answer:
Tomtit [17]3 years ago
8 0
This is for 30cm not 48 but you can find out how to do it. This is an example

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Complete the following statement. Round to the nearest hundredth .
RSB [31]

f(x) = 3/(x + 2) - √x - 3

f(7) = 3/(7 + 2) - √7 - 3

f(7) = 3/9 - √4

f(7) = 0.333 - 2

f(7) = -1.67

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3 years ago
I need help I don’t understand this
alex41 [277]

This is the solution hope you can understand, i apologize for the bad handwriting

4 0
3 years ago
What is the domain of g?
Mrac [35]

Answer:

Solution. The domain of g(x) consists of all real numbers except x = 32, since that input value would cause us to divide by 0. Likewise, the domain of f consists of all real numbers except 1. So we need to exclude from the domain of g(x) that value of x for which g(x) = 1.

Step-by-step explanation:

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3 years ago
Help, this is due now... HELP
kkurt [141]

Answer:

100 1/4

Step-by-step explanation:

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3 years ago
What is the area of this compound shape?
Paraphin [41]

Answer:

139.36

Step-by-step explanation:

first you do 8*8 because that would be the area of the square part

8*8=64

then find the area of the semicircle

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A=3.14R^2/2

3.14*4^2/2

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50.24/2

25.12

now because there are 3 of the semicircles you do

25.12*3

75.36

then you add the 64 from the square to get your answer

75.36+64

139.36

6 0
3 years ago
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