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Contact [7]
3 years ago
5

A rain gutter is to be constructed from a metal sheet of width 48 cm by bending up one-third of the sheet on each side through a

n angle θ.
Show that the cross-sectional area of the gutter is modeled by the function
A(θ) = 256 sin(θ) + 256 sin(θ) cos(θ).

For what angle θ is the largest cross-sectional area achieved?

Mathematics
1 answer:
Tomtit [17]3 years ago
8 0
This is for 30cm not 48 but you can find out how to do it. This is an example

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14. A quadratic equation is graphed above.
IrinaVladis [17]

Answer:

D.

Step-by-step explanation:

2=-2,3=-3

2²=-2²,3²=3²

3 0
3 years ago
What is the area of the figure:
Luba_88 [7]

For this case we have that the area of the triangle is given by:

A = \frac {b * h} {2}

Where:

b: It's the base

h: It's the height

We have to:

cos (45) = \frac {b} {24}\\b = 24 * cos (45)\\b = \frac {\sqrt {2}} {2} * 24\\b = 12 \sqrt {2}

The atura will be given by:

sin (45) = \frac {h} {24}\\h = 24 * sin (45)\\h = \frac {\sqrt {2}} {2} * 24\\h = 12 \sqrt {2}

So, the area is:

A = \frac {12 \sqrt {2} * 12 \sqrt {2}} {2}\\A=\frac{(12\sqrt{2})^2}{2}\\A = 144

Answer:

144

6 0
3 years ago
Read 2 more answers
A secret formula for eternal youth, f (x), was discovered by Dr. Quick, who has been working in our biotech company. However, Dr
charle [14.2K]

Answer:9

Step-by-step explanation:3x3= 9

(X3x3x3)

=9p

8 0
4 years ago
11. GARDEN Emily calculates that the area of a flower garden is 28.125. She measured
Svetlanka [38]

Answer:

A=28.13 Sq Ft

Step-by-step explanation:

Given that the length of the garden = 4.5 ft

Breadth of the garden = 6.25 ft

Area is given by the formula

A=length x breadth

A=4.5 x 6.25 sq ft

A= 28.125 sq ft

Here if we round the area to the nearest hundredth, the area will be

A=28.13 Sq Ft

7 0
3 years ago
When i am solving for the sides of a right triangle when will i use trigonometric functions
AnnZ [28]

Answer:

The ratios of the sides of a right triangle are called trigonometric ratios. We need to use trigonometric functions to find them when we don't have any angle other than 90 degree shown.

Three common trigonometric ratios are the sine (sin), cosine (cos), and tangent (tan). These are defined for acute angle.

However when we have one angle given with the 90 degree we can deduct without trigonometry but we would use all angles to find the hypotenuse or all angles to find the side of a right angle.

Alternatively, we cna do this with one given angle but if we have one, we might as well work out the other one without trigonometry and do a division with Sin = 25 (sin 35) sin 90  / sin 55

is one example when given the base 25ft that would find the hypotenuse or the length of elevation for buildings looking down or zip-wire questions.

Step-by-step explanation:

       A

       |  \

       l     \

4cm|        \ 5cm

       |          \

       |            \

   B | -  -  -  -  \ C      

          3cm

Suppose we wanted to find sin( A) in△ABC    

(The height of the wall in elevation questions would be used above the base shown 3cm at the start) Sin = 3 (sin 35)° sin 90°  / sin 55° to find the height side (4).

Sine is defined as the ratio of the opposite to the hypotenuse

sin(A) =  hypotenuse          ​= AB/BC        = 3/5

             / opposite

                                           

​

​

6 0
3 years ago
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