A rain gutter is to be constructed from a metal sheet of width 48 cm by bending up one-third of the sheet on each side through a
n angle θ.
Show that the cross-sectional area of the gutter is modeled by the function
A(θ) = 256 sin(θ) + 256 sin(θ) cos(θ).
For what angle θ is the largest cross-sectional area achieved?
1 answer:
This is for 30cm not 48 but you can find out how to do it. This is an example
You might be interested in
Answer:
6x+36=180
6x=144
x=24
Step-by-step explanation:
this is the correct answer
Answer:
c. 22/24
Step-by-step explanation:
perimeter = 3/8 + 3/8 + 1/6
perimeter = 22/24 or 11/12
Since it’s a square all sides are even. Meaning you multiply 7/12 by 4. Giving you 7/3 or 2 ⅓. Hope this helps!
1 Liter = 1000 mL
so....
1.5 Liter = 1500 mL
Answer:
12b+1
Step-by-step explanation:
-4 + 4b + 5 + 8b
12b+1