The system shown at the right has no solution, as the grahs never intersect.
On the other hand, the line and the parab. at the left do intersect, and the points of intersection are (-3,0) and (6,6).

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3 years ago

A system of two equations is shown below. What will you need to multiply the

irga5000 [103]

Answer:

the right answer is : -3

Step-by-step explanation:

$\left \{ {{x+y=4} \atop {3x+4y=14}} \right. \\\left \{ {{-3(x+y)=-3*4} \atop {3x+4y=14}} \right. \\\left \{ {{-3x-3y=-12} \atop {3x+4y=14}} \right. \\\left \{ {{-3x-3y+3x+4y=2} \atop {3x+4y=14}} \right. \\\left \{ {{-3y+4y=2} \atop {3x+4y=14}} \right. \\\left \{ {{y=2} \atop {3x+4*2=14}} \right. \\\left \{ {{y=2} \atop {3x=14-8=6}} \right. \\\left \{ {{y=2} \atop {x=\frac{6}{3}=2 }} \right.$