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3 years ago

Find the value of x. Round to the nearest tenth. PLEASE HELP ME!!

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

7 0

Answer:

Step-by-step explanation:

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=x,\ leg=15.6cm:2=7.8cm,\ hypotenuse=8.8cm$

Substitute:

$x^2+7.8^2=8.8^2$

$x^2+60.84=77.44$ <em>subtract 60.84 from both sides</em>

$x^2=16.6\to x=\sqrt{16.6}\\\\x\approx4.1\ cm$

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