Let's call L the width of the rectangle and W its width. The area of the rectangle is the product between the length and the width, and we are also told that the area is 300 square meters, so we can write

Moreover, we know that the length is 5 meters longer than the width:

We have a system of 2 equations in 2 unknown variables, L and W. If we substitute the second equation into the first one, we get


which has two solutions: W=-20 and W=15. We can discard the negative solution since it does not have physical meaning, and now we can substitute the value of W into the second equation to find L:

<span>Therefore, the rectangle has width 15 meters and length 20 meters.</span>
I would start by plugging in a number for x. Just any random number. Let's take 2 for example. Then the equation would go from 2x + y = -4, to 2(2) + y = -4. Then solve.
2(2) + y = -4
4 + y = -4, after you've done that, plug in a number for y, that completes the equation. In this case, the only acceptable number, would be -8. Because it completes the number sentence.
4 + (-8) = -4
-4 = -4.
Now plug in other numbers, to get the same outcome. Hope this helped!
-Twixx
Answer:
D)commodity,representative,filat