Question

Please help, I have been trying for a while :(question on photo​

Answer 1

Answer:

$\frac{x-22}{(x+2)(x-4)}$

Step-by-step explanation:

multiply the numerator/denominator of the first fraction by (x - 4)

multiply the numerator/denominator of the second fraction by (x + 2)

this ensures that the fractions have a common denominator

$\frac{4}{x+2}$ - $\frac{3}{x-4}$

= $\frac{4(x-4)}{(x+2)(x-4)}$ - $\frac{3(x+2)}{(x+2)(x-4)}$ ← subtract numerators leaving the common denominator

= $\frac{4x-16-3x-6}{(x+2)(x-4)}$

=$\frac{x-22}{(x+2)(x-4)}$