None of the answers are correct because it’s definitely not “Given” because x=20 is like an answer. It’s also not “Distributive Property”, “subtraction Property”, and or “Additional Property” b/c there’s nothing that can be distributed, subtract or add. It’s just an answer.
Answer:
12p=48
Step-by-step explanation:
Answer:

Step-by-step explanation:
We start by subtracting
from both sides of the second inequality:

Therefore, we conclude that:

Therefore, every point that satisfies the system has a
-coordinate greater than
.
Hello,
Your answer would be:
The parent function is : f ( x ) = x³
f ( x + 3 ) = ( x + 3 )³
shift to the left 3 units.
Plz mark me brainliest!
Hope this helps!
Answer:
The area of the triangle is 
Step-by-step explanation:
Given:
Coordinates D (0, 0), E (1, 1)
Angle ∠DEF = 60°
△DEF is a Right triangle
To Find:
The area of the triangle
Solution:
The area of the triangle is = 
Here the base is Distance between D and E
calculation the distance using the distance formula, we get
DE = 
DE =
DE = 
DE = 
Base = 
Height is DF
DF =
DF = 
DF = 
Now, the area of the triangle is
= 
=
=
=