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Firlakuza [10]
3 years ago
15

You look at real estate ads for houses in Naples, Florida. There are many houses ranging from $200,000 to $500,00 in price. The

few houses on the water, however, have prices up to $15 million. The distribution of the prices will be:______.
a) skewed to the left.
b) roughly symmetric.
c) skewed to the right.
d) unimodal.
e) too high.
Mathematics
1 answer:
cricket20 [7]3 years ago
5 0

Answer:

c) skewed to the right.

Step-by-step explanation:

We need to remember that is a distribution is skewed to the right then we have the following condition satisfied:

Mode< Median

And if is skewed to the left then we have:

Mean

If the distribution is symmetric we need to satisfy:

Mean = Median=Mode

For this case since we have most of the values between 200000 and 500000 when we put atypical values like 15000000 that would affect the sample mean and on this case the sample mean would larger than the sample median because the median is a robust measure of central tendency not affected by outliers.

So for this special case we can say that the Mean>Median. And probably the median would be higher than the mode so then we can conclude that the best answer for this case would be:

c) skewed to the right.

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Which expression is NOT equivalent to 24 + 12?
Ksju [112]

Answer: 2(12+6) bc you do the work in parentheses first. Then after you multiply 18 by 2 which is 36. Sorry I suck at explaining stuff

Step-by-step explanation:

7 0
3 years ago
Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.
statuscvo [17]

Answer:

A, D, E are true

Step-by-step explanation:

You have to complete the square to prove A.  Do this by first setting the function equal to 0, then moving the 5 to the other side.

x^2-8x=-5

Now we can complete the square.  Take half the linear term, square it, and add it to both sides.  Our linear term is 8 (from the -8x).  Half of 8 is 4, and 4 squared is 16.  So we add 16 to both sides.

(x^2-8x+16)=-5+16

We will do the addition on the right, no big deal.  On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex.  We will rewrite with that perfect square on the left and the addition done on the right,

(x-4)^2=11

Now we will move the 11 back over, which gives us the k coordinate of the vertex.

(x-4)^2-11=y

From this you can see that A is correct.

Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.

The axis of symmetry is also found in the h value.  This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation.  In the case of this type of parabola, that "x = " will always be equal to the h value.  So the axis of symmetry is

x = 4, which is why C is NOT correct, either.

We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x.  When we do that, and then solve for y, we find that when x = 0, y = 5.  So the y-intercept is (0, 5).

From this you can see that D is also correct.

To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x.  I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice.  Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0).  That's why you need the quadratic formula to find these values.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B9x%7D%5E%7B2%7D%20-%20%7B%28x%7D%5E%7B2%7D%20-%204%29%20%7B%7D%5E%7B2%7D%20
Alenkinab [10]

Answer:

{ x^2+3x-4}

Step-by-step explanation:

Factor top and bottom.

The numerator is a difference of two squares, and the denominator is a quadratic.

\frac{ {9x}^{2} - {(x}^{2} - 4)^{2} }{4 + 3x - {x}^{2} }

= \frac{ (3x+x^2-4)(3x-x^2+4) }{(1+x)(4-x)}

= \frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)}

If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give

= { (x-1)(x+4)}

= { x^2+3x-4}

3 0
3 years ago
Read 2 more answers
The sum of 5 consecutive integers is 505
kramer
Using algebra:n+(n+1)+(n+2)+(n+3)+(n+4)=5055n+10=5055n=505-105n=495n=495/5n=99n+1=100n+2=101 answer
5 0
3 years ago
A has $32 more than B, and B has five times as much money as C. If C has d dollars, how much does A have? Answer:
Hoochie [10]

A = B+32

B = 5C

A = 5C+32

C has d dollars so replace d for c

A = 5d+32

7 0
3 years ago
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