Answer:
Step-by-step explanation:
v = {[(20sin36°)i + (20cos36°)j] + 10i} mi/h
vE = 20sin36º + 10 = 21.76 mi/h
vN = 20cos36° = 16.18 mi/h
v = √(vE2 + vN2) = √(21.762 + 16.182) mi/h = 27.12 mi/h
θ = tan-1(vN/vE) = tan-1(16.18/21.76) = 36.6º north of east
Answer:
The distance of needle cover as it rotate is 0.700688 cm
Step-by-step explanation:
Given as :
The length of the needle = r = 24 cm
The needle is rotated at angle = Ф = 96°
The distance of needle cover as it rotate = length of arc made = l cm
The radius of arc = length of needle = r cm
<u>Now, According to question</u>
The distance of needle cover as it rotate = 
where , π = 3.14
Or, l = 
Or, I = 
Or, l = 75.36 × 0.533°
∵ 180° = 3.14 radian
So, 0.533° = 0.0092978
So, l = 75.36 × 0.0092978
∴ l = 0.700688 cm
So,The distance of needle cover as it rotate = l = 0.700688 cm
Hence, The distance of needle cover as it rotate is 0.700688 cm Answer
Personally I think the answer would be c. Cross multiplication
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