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3 years ago

Find the value of x in the triangle shown below. = 2 45° 98

Mathematics

1 answer:

NeX [460]3 years ago

8 0

Answer:

Hello! answer: x = 37

Step-by-step explanation:

Triangles add up to 180 degrees 45 + 98 = 143

180 - 143 = 37 therefore the missing angle is 37 HOPE THAT HELPS!

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One afternoon, Supreme sub shop sells 15 subs in 45 minutes. If the shop continues to sell subs at the same rate, about how many

melomori [17]

60 subs
Because it’s 15 per 45 and 45 times 4 is 180 which means that in 3 hours or 180 minutes they sold 15 times 4 amount of subs and 15 times four is 60. Hope this helps. Sorry if the explanation isn’t that good

3 0

3 years ago

The question is number 6 i don't know if I got it right I really need to know and this is solving quadratics by completing the s

zhenek [66]

Answer:

Step-by-step explanation:

If u = 6 then substitute so

6(6+6)=6 know solve but this isn't going to be correct because 6 plus 6 is 12 times 6 isn't 3

So your answer isn't correct. I think it would be a negative number or decimal because 6 is larger than 3. Hope this helps!

it is u(u+6)=3

I got u=6

4 0

3 years ago

Can someone help me with this<br><br>25t = 5( 5t + 1)

Elenna [48]

That equation has no solutions.

5 0

4 years ago

The length of a rectangle is 4 cm greater than the width of the rectangle.

Sunny_sXe [5.5K]

Answer: a) 9 cm

explanation: since the length of the rectangle is 4 cm greater than the width, you can just take 9 cm (the length) minus 4, which gets you 5 cm. if we use the area formula (length x width), then 9 x 5 = 45 square cm.

5 0

3 years ago

Assume that all the given functions have continuous second-order partial derivatives. If z = f(x, y), where x = 9r cos(θ) and y

vfiekz [6]

Answer with Step-by-step explanation:

We are given that all the given functions have continuous second-order partial derivatives.

$z=f(x,y)$

Where $x=9rcos\theta,y=9r sin\theta$

We have to find

A. $\frac{\delta z}{\delta r}$

We know that

$\frac{\delta z}{\delta r}=\frac{\delta z}{\delta x}\frac{\delta x}{\delta r}+\frac{\delta z}{\delta y}\frac{\delta y}{\delta r}$

Using this formula

$\frac{\delta z}{\delta r}=9cos\theta \frac{\delta z}{\delta r}+9sin\theta\frac{\delta z}{\delta r}$

$\frac{\delta z}{\delta r}=\frac{x}{r}\frac{\delta z}{\delta r}+\frac{y}{r}\frac{\delta z}\delta y}$

B. $\frac{\delta z}{\delta \theta}$

$\frac{\delta z}{\delta \theta}=\frac{\delta z}{\delta x}\frac{\delta x}{\delta\theta }+\frac{\delta z}{\delta y}\frac{\delta y}{\delta\theta}$

$\frac{\delta z}{\delta \theta}=-9rsin\theta\frac{\delta z}{\delta x}+9rcost\theta\frac{\delta z}{\delta y}$

$\frac{\delta z}{\delta \theta}=-y\frac{\delta z}{\delta x}+x\frac{\delta z}{\delta y}$

C. $\frac{\delta^2 z}{\delta r\delta\theta}$

$\frac{\delta^2 z}{\delta r\delta\theta}=-9sin\theta\frac{\delta z}{\delta x}-y\frac{\delta^2z}{\delta x^2}(9cos\theta)+9 cos\theta\frac{\delta z}{\delta y}+x\frac{\delta^2z}{\delta y^2}(9sin\theta)$

$\frac{\delta^2 z}{\delta r\delta\theta}=-9sin\theta\frac{\delta z}{\delta x}-(81rsin\theta cos\theta)\frac{\delta^2z}{dx^2}+9cos\theta\frac{\delta z}{\delta y}+(81r cos\theta sin\theta)\frac{\delta^2z}{\delta y^2}$

$\frac{\delta^2 z}{\delta r\delta\theta}=-\frac{y}{r}\frac{\delta z}{\delta x}-\frac{xy}{r}\frac{\delta^2}{\delta x^2}+\frac{x}{r}\frac{\delta z}{\delta y}+\frac{xy}{r}\frac{\delta^2z}{\delta y^2}$

3 0

3 years ago