Algebra 1 Homework Thanks to whoever helps, have a nice day;)
2 answers:
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Answer:
Perimeter of one triangle is 65 dm
Perimeter of other triangle is 52 dm
Step-by-step explanation:
Please remember the concept
If sides are in the ratio of a:b
Then the area in the ratio of
It is given sum of their perimeter is 117.
Let the small triangle has perimeter as x.
So, perimeter of big triangle is 117-x.
So, we can set up equation as
Cross multiply
50(117-x)^2 =32x^2
Expand the left side
50=
Distribute the left side
684450-11700x+=
Subtract both sides and rewrite it
Solve this quadratic for x.
Divide both sides of the equation by 18 to simplify.
-650 x+38025=0
Now, if possible let's factor
Find two integers whose multiplication is 38025 but adds to -650.
-65 and -585 works.
So, we can rewrite it as
(x -65)(x-585) =0
Solve them using zero product property
x=65, x=585
So, x=65 works here.
So, perimeter of one triangle is 65 dm
Perimeter of other triangle is 117-65= 52 dm
Answer:
D2=21/24 mile
Step-by-step explanation:
Her it is not specified if it is base or height, it only talks about dimensions, so let's work with dimensions
A=1/12
D1=4/21mile, D2=?
Area of a triangle
A=((D1*D2)/2) → 2A=D1*D2 → D2=2A/D1 so D2=(2*1/12)/(4/21) =(1/6)/(4/21) = (1*21)/(6*4)=21/24 mile