Answer:
0.7486 = 74.86% observations would be less than 5.79
Step-by-step explanation:
I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The general format of the normal distribution is:
N(mean, standard deviation)
Which means that:
What proportion of observations would be less than 5.79?
This is the pvalue of Z when X = 5.79. So
has a pvalue of 0.7486
0.7486 = 74.86% observations would be less than 5.79
Answer:
15% 30% 50% 75% 89%
Step-by-step explanation:
u change 0.15 to a function 15/100 then the one hungred below is persent
The equation that can be used to represent total tickets sales is 2170 = 5s + 2f + 10a
<h3>Equation</h3>
let
- Number of students tickets = s
- Number of faculty tickets = f
- Number of alumni tickets = a
Expression for number of students tickets sold;
s = f + 15
Expression for number of faculty tickets sold;
f = 2a
Expression for number of alumni tickets sold;
f = 2a
a = f/2
- Cost of students tickets = $5
- Cost of faculty tickets = $2
- Cost of Alumni tickets= $10
- Total revenue = $2170
2170 = 5s + 2f + 10a
Learn more about equation:
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