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3 years ago

12

M

alt="m {2} - m - 2 = 0" align="absmiddle" class="latex-formula">

1 answer:

Serjik [45]3 years ago

4 0

Answer:

m=2-2

m=0

Step-by-step explanation:

U need to do substitution

So u carry both 2 from that side to cross the equal to sign. One becomes positive because it is carrying a negative sign at the other side

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Which can be used to solved the expression (r^-4)^3

Oksana_A [137]

Answer:

The expression is equal to 1 over 12 factors of r

Multiplying the exponents will create an equivalent expression.

Step-by-step explanation:

We are given the following in the question:

$(r^-^4)^3$

<h3>Properties of exponent: </h3>

$(x^m)^n=x^m^n$

$x^-^a=\frac{1}{x^a}$

Thus, we can simplify the given expression as:

$(r^-^4)^3$

= $r^-^1^2$

= $\frac{1}{r^1^2}$

Thus, the correct answer is:

Option 2) The expression is equal to 1 over 12 factors of r

Option 4) Multiplying the exponents will create an equivalent expression.

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3 years ago

A food-packaging apparatus underfills 10% of the containers. Find the probability that for any particular 10 containers the numb

Maksim231197 [3]

Answer:

a) $P(X = 1) = 0.38742$

b) $P(X = 3) = 0.05740$

c) $P(X = 9) = 0.00000$

d) $P(X \geq 5) = 0.00163$

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 10 containers, so $n = 10$ .

A food-packaging apparatus underfills 10% of the containers, so $p = 0.1$ .

a) This is P(X = 1)

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

b) This is P(X = 3)

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

c) This is P(X = 9)

$P(X = 9) = C_{10,9}.(0.1)^{9}.(0.9)^{1} = 0.00000$

d) This is $P(X \geq 5)$ .

Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:

$P(X < 5) + P(X \geq 5) = 1$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.34868$

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X = 2) = C_{10,2}.(0.1)^{2}.(0.9)^{8} = 0.1937$

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

$P(X = 4) = C_{10,4}.(0.1)^{1}.(0.9)^{9} = 0.38742$

So

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.34868 + 0.38742 + 0.19371 + 0.05740 + 0.01116 = 0.99837$

Finally

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.99837 = 0.00163$

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3 years ago

A student has $5.00 to spend on a poster, paint, and stickers. The total cost for the

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Answer:

2.8+.55x=5 x=4

Step-by-step explanation:

5-2.8=2.2

2.2/.55=4

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Answer:

Step-by-step explanation:

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