In general, you're calculating the magnitude of average velocity. In fact, speed is a vector, and as such it also has a direction and orientation.
So, if you compute the average speed, you're assuming that you went directly from point A to point B, which is basically never the case.
If, instead, you actually moved on a straight line from point A to point B, then the two quantities are the same.
Answer:
the height of the flagpole is 5 meters
Step-by-step explanation:
The computation of the height of the flagpole is given below
Given that
the length of the rope is 13 meters
And, the ground would be 12 meters
Based on the above information, the height of the flagpole is
= √13^2 - √12^2
= √169 - √144
= √25
= 5 meters
hence the height of the flagpole is 5 meters
A.) m=5/6
B.) y
=5/6x-3 use the slope formula y=mx+b
C.) y
-y1 = m(x-x1)
Answer:
Step-by-step explanation:
P1 = (2000, 1000) in the form (x1,y1)
P2 = (2012, 3400) in the form (x2,y2)
m = (y2-y1 / x2-x1)
m = ( 3400-1000 ) / (2012 - 2000)
m = 2400 / 12
m = 200
y = 200x + 800
