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Anna007 [38]
3 years ago
12

HELP

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

Luciano

Step-by-step explanation:

Luciano is going 4.5 minutes per mile.

Anthony is going 5.23 minutes per mile.

Luciano is going about 0.73 minute faster than anthony

You might be interested in
1.) Is y= cosx/x an even, odd , or neither <br><br> 2.) Is y=sinx/x and even, odd , or neither
Marrrta [24]

Answer:

Step-by-step explanation:

1) y = (cos x) / x is neither, since cos x is even and x is odd.  Expressions such as this are neither even nor odd. /

2) y = (sin x) / x is even, since sin x and x would either both be positive at the same time or negative at the same time.  Recall that (-) / (-) is positive, just as (+) / (+) is positive.

6 0
3 years ago
Can the sides of a triangle have lengths 2.4, 6.5, and 7.4?
Ira Lisetskai [31]

Answer:

yes.

Step-by-step explanation:

2.4 + 6.5 = 8.9 (triangle inequality)

8.9 > 7.4

= it is possible to make a triangle wit these measurements.

4 0
3 years ago
There are 32 pupils in a class. 20 of them are girls. What is the ratio of boys to girls in it’s simplest form
Ray Of Light [21]

Hello!

If there are 32 people in total in the class, and 20 of them are girls, that means there are 12 boys in the class

so the ratio of boys to girls is 12:20

to get simplest form, divide by the greatest common factor. which in this case, is 4.

12 / 4 = 3

20 / 4 = 5

your final answer is: boys:girls, 3:5

I hope this helps, and have a nice day!

7 0
3 years ago
Alex had brochures printed for their new business venture. Originally he ordered 3 boxes of black-and-white brochures and 4 boxe
drek231 [11]

Answer:

Colored: $28

Normal: $11

Step-by-step explanation:

4 0
3 years ago
If (ax+b)(bx+a)=26x^2+ Box(x) +26, where a, b, and Box are distinct integers, what is the minimum possible value of Box, the coe
timurjin [86]

Answer:

16.59

Step-by-step explanation:

Given:

(ax+b)(bx+a)=26x^2+\Box\cdot x+26

Expanding the left hand side, we have:

(ax+b)(bx+a)=abx^2+a^2x+b^2x+ab\\=abx^2+(a^2+b^2)x+ab\\=26x^2+\Box\cdot x+26\\ab=26 \implies b=\frac{26}{a}

Therefore:

a^2+b^2=a^2+\dfrac{26}{a} =\dfrac{a^3+26}{a}

To find the minimum value, we take the derivative and solve for its critical point.

\frac{d}{da} (\frac{a^3+26}{a})=\frac{2a^3-26}{a^2}\\$Setting the derivative equal to zero, we have:\\2a^3-26=0\\2a^3=26\\a^3=13\\a=\sqrt[3]{13}

Recall that:

\Box=a^2+b^2=\dfrac{(\sqrt[3]{13}) ^3+26}{\sqrt[3]{13}}\\=\dfrac{13+26}{\sqrt[3]{13}}\\\\\Box=16.59

The minimum possible value of the coefficient of x is 16.59.

5 0
3 years ago
Read 2 more answers
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